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Mama L [17]
3 years ago
6

Which communication technology should you use if you need to connect three offices which are all within 3 miles of each other at

speeds up to 75 Mbps using antennas?
Computers and Technology
1 answer:
Serhud [2]3 years ago
7 0

Answer: WiMax (Worldwide Interoperability for Microwave Access)

Explanation: Worldwide Interoperability for Microwave Access(WiMax) is the technology with the wireless broadband that helps in the long distance communication.

The base station in WiMax is installed in the area of the service provider and the receivers are placed at the client's outlet.Thus, WiMax is used for the connection of the three offices as it can connect offices with the range of 3 miles and provides the connectivity  with the speed upto 75 Mbps

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Explanation:

Footer: This is a text which appears in the bottom of every page. Mostly page numbers and the name of the publisher or the company name will be in the footer.

Page Color: This represents the color of the page

Page border: This option provides border to the page. The border can be thin or thick according to the requirement.

Watermark: This is the right answer. A watermark is added such that your content cannot be used by anyone else without permission. When you copy the text, the water mark also gets copied, thus avoiding plagiarism.

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3 years ago
1.The character escape sequence to force the cursor to go to the next line is________: 2. The character escape sequence to force
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Answer:

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Read 2 more answers
The ticketing system at the airport is broken, and passengers have lined up to board the plane in the incorrect order. This line
wolverine [178]

Answer:

See explaination

Explanation:

The program code

import java.util.ArrayList;

public class Main

{

public static void main(String[] args)

{

ArrayList<AirlineTicket> tickets = new ArrayList<AirlineTicket>();

//This creates a randomized list of passengers

addPassengers(tickets);

for(AirlineTicket elem: tickets)

{

System.out.println(elem);

}

//This creates a TicketOrganizer object

TicketOrganizer ticketOrganizer = new TicketOrganizer(tickets);

//These are the methods of the ticketOrganizer in action

System.out.println("\nPassengers Ordered by Boarding Group:");

ticketOrganizer.printPassengersByBoardingGroup();

System.out.println("\nPassengers in line who can board together:");

ticketOrganizer.canBoardTogether();

}

//Do not touch this method! It is adding random passengers to the AirlineTicket array

public static void addPassengers(ArrayList<AirlineTicket> tickets)

{

String[] seats = {"A","B","C","D","E","F"};

for(int index = 0; index< 15; index++)

{

int random = (int)(Math.random() * 5);

AirlineTicket ticket = new AirlineTicket("Passenger " + (index+1), seats[random], ((int)(Math.random()*5)+1), ((int)(Math.random()*8)+1));

tickets.add(ticket);

}

}

}

class TicketOrganizer

{

private ArrayList<AirlineTicket> tickets ;

//constructor with parameter as an arraylist of AirlineTicket

public TicketOrganizer(ArrayList<AirlineTicket> tickets)

{

this.tickets = tickets;

}

//methhods to return the arraylist of airlines

public ArrayList<AirlineTicket> getTickets()

{ //re-organize the ticket first

ArrayList<AirlineTicket> tickets_organized = new ArrayList<AirlineTicket>();

for(int i=1; i<=5; i++)

{

for(AirlineTicket ticket: tickets)

{

if(ticket.getBoardingGroup() == i)

{

tickets_organized.add(ticket);

}

}

}

return tickets_organized;

}

//print the tickets based on boardingGroup

public void printPassengersByBoardingGroup()

{

int count = 0;

for(int i=1; i<=5; i++)

{

System.out.println("Boarding Group " + i + ":");

for(AirlineTicket ticket : tickets)

{

if(ticket.getBoardingGroup() == i)

{

System.out.println("Passenger " + ticket.getName());

}

}

}

See attachment for sample output

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