Plug in 1
and −1
to get two values of r(x)
which is linear. From there you can get what a,b
are in ax+b.
Since
f(x)=g(x)(x+1)(x−1)+r(x)
we have
f(1)=g(1)(1+1)(1−1)+r(1)=r(1)=−10
f(−1)=g(1)(−1+1)(−1−1)+r(−1)=r(−1)=16
We know the remainder is of degree 1
, so
r(x)=ax+b
and now we know,
r(1)=ax+b=a+b=−10
r(−1)=ax+b=−a+b=16
so, solve
a+b=−10
−a+b=16
which yields, a=−13
b=3
, so
r(x)=−13x+3
Jade owes the bank a little more than $50
Answer:
Step-by-step explanation:
Antelope, Montana:
21, 30, 42, 58, 70, 79
Range- 58 79-21= 58
Quartile 1- 30
Quartile 3- 70
Interquartile Range- 40 70-30= 40
Augusta, Maine:
28, 32, 41, 53, 66, 75
Range- 47
Quartile 1- 32
Quartile 3- 66
Interquartile Range- 34
A) $3500*0.055 = $192.50 . . . . the interest paid each year
B) The problem makes no mention of compounding, so we assume simple interest is paid. (Most accounts do not work this way.)
.. at the end of 1 year, 3500 +192.50 = $3692.50
.. at the end of year 2, 3692.50 +192.50 = $3885.00
.. at the end of year 3, 3885.00 +192.50 = $4077.50
.. at the end of year 4, 4077.50 +192.50 = $4270.00
.. at the end of year 5, 4270.00 +192.50 = $4462.50
The answer is C. (-2, -3). If you plug the x and y coordinates into the equation, it’ll be -24 which is less than -2.