There are two of them.

I don't know a mechanical way to 'solve' for them.

One can be found by trial and error:

x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
x=4 . . . . . 2^4 = 16 . . . . 4(4) = 16 . . . . Yes ! That works ! yay !

For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.

The point is near, but not exactly, x = 0.30990693...

If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks. If anybody out there has it, I'm
waiting with all ears.

7 0

2 years ago

Read 2 more answers

6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A

Alexxx [7]

Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

$42 + 0.72m = 70 + 0.12m$