Please help me. I will fail...I will mark you brainiest.
1 answer:
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Answer:
Step-by-step explanation:
You first need to determine if the ellipse is horizontal or vertical, which can be found by the length of the major axis.
The vertices are at (18,1) and (-10,1). The distance is 28 units. (horiz)
The co-vertices are at (4,14) and (4,-12) The distance 26 units (vert)
The major axis is horizontal, so the standard form of the ellipse is
where (h,k) are the coordinates of the center.
To find the center, find the midpoint of the major axis
The center is at (4,1)
Since the major axis is 2a, a would be 28 divided by 2=14 squared : 196
The minor axis is 2b, so b would e 26/2=13 squared: 169
Inserting the center and a,b values into the standard form eq:
hope this helps.
The graph intersects the x-axis twice. It intersects at the points of (-1,0) and (2.5,0). The graph is attached.
9514 1404 393
Answer:
a ≈ 4.68
Step-by-step explanation:
The law of cosines tells you ...
a² = b² +c² -2bc·cos(A)
a = √(b² +c² -2bc·cos(A))
a = √(5² +8² -2·5·8·cos(33°)) = √(25 +64 -80·0.83867) ≈ √21.906
a ≈ 4.68
