Please help me. I will fail...I will mark you brainiest.

Insert commas to show periods according to Indian as well as International place value system of 2349812

Nata [24]

Answer:

23,49,812

Step-by-step explanation:

3 0

3 years ago

Need help on these !! 13 and 14! Please!!

katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.

Step-by-step explanation: 

As the general sine function is given by

$y=asin(bx+c)+d$ .......[A]

amplitude = a
period = 2π ÷ b
Phase shift = -c ÷ b
Vertical shift = d

As in the question,

amplitude = a = 4
period = 4π
phase shift = -4π/3
Vertical shift = d = -2

As

period = 2π ÷ b

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b

c = b × 4π/3

c = 1/2 × 4π/3

c = 4π/6

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

$y=asin(bx+c)+d$

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2

Note: The graph is also shown in attached diagram.

Question # 14

Answer:

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

Step-by-step explanation: 

As the general cotangent function is given by

$y=acot(bx+c)+d$ .......[A]

amplitude = a
period = π ÷ b
Phase shift = -c ÷ b
Vertical shift = d

As in the question,

period = π
phase shift = -π/3
Vertical shift = d = 2

As

period = π ÷ b

b = π/period

b = π/π ∵ period = 4π

b = 1

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b

c = b × π/3

c = 1 × π/3

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and c = π/3 in Equation [A] would bring us the required equation for the given function.

$y=acot(bx+c)+d$

y = cot(x+π/3)+2

Note: The graph is also shown in attached diagram.

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0

3 years ago

A bag contains

Natasha2012 [34]

1/15 because you add all the blocks together and it gives you 15 and there is only 1 blue block so it will be a 1/15 chance of getting it

8 0

3 years ago

FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli

____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0

1 year ago

An airplane is traveling at a speed of 240 miles/hour with a bearing of 110°. The wind velocity is 56 miles/hour at a bearing of

vodka [1.7K]

Answer:

Actual speed = 288 miles per hour

Actual direction angle = $116.38^\circ$

Step-by-step explanation:

"Bearing" is the relative position of an object outside the plane compared to the position of the plane.

Heading the the direction the nose of the plane is pointing.

Course is the direction that pilot wants the plane to go.

Wind direction is always the direction the wind is blowing from.

The airplane is traveling at a speed of 240 miles/hour with a bearing of 110°.

If the plane is traveling with a bearing of 110° and the wind is blown at a bearing of 325°.

$325^{\circ}- 110^{\circ} =225^{\circ}$

$215^{\circ}- 180^{\circ} =35^{\circ}$

The Ground speed will be in excess of the airspeed and true direction will be south if the indicated heading.

The tailwind component is:

$56 cos (35^\circ)$

And the cross wind component is:

$56 sin (35^\circ)$

And that is,

$C^2 = (286)^2 + (32)^2$

$c = 288$

So the actual speed of the plane is 288 miles per hour.

The deviation in the direction is:

Let the direction angle be 'x'.

$x = tan ^{-1}\left ( \frac{32}{286} \right )=6.38^\circ$

So the actual direction angle is $110^\circ+ 6.38^\circ=116.38^\circ$ .

5 0

3 years ago