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podryga [215]
3 years ago
8

A line passes through the points (8, 10) and (9, 10). What is its equation in slope-intercept form?

Mathematics
1 answer:
mash [69]3 years ago
4 0
I’m pretty sure that in slope intercept form it will be y-10=(0/1)(x-8)
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Meg constructed triangle POQ and then used a compass and straightedge to accurately construct line segment OS, as shown in the f
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In order to understand this question, one needs to understand the construction first. After creating POQ, Meg picks a radius r and makes a circle around O. There are 2 points where the circle meets the triangle. Then, she meets another radius and she makes a circle of radius s around each of the points on the triangle. The two circles cross at one point, as can be seen in the figure. Let's name the first two points A and B and let's name the last point S. We have that for the triangles OAS, OBS we have OA=OB=r, BS=AS=s and that OS is common to both. Thus by the S-S-S triangle equality theorem, the triangles are equal. Hence for the angles AOS=BOS, namely POS=QOS. Since POQ=POS+QOS, we have that POS has to be half of POQ. The only consistent choice is the third one, POS=20 degrees and POQ=40 degrees.
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3 years ago
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Answer:

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VladimirAG [237]
Use Subtraction

1. Subtract
x+2y=7
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Korolek [52]

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In this case, "simplify" directs that you 1) carry out the indicated multiplication and 2) combine like terms.

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