All categories

3 years ago

If DB = 36 and AC = 3x - 3, what is the value of x?

Mathematics

1 answer:

algol133 years ago

3 0

Answer:

A.) 13

Step-by-step explanation:

Since DB =36, and AC is the same line, then AC = 36. The new equation is 36 = 3x - 3. Do inverse operation. Add 3 to both sides of the equation: 36+3=39 & -3+3=0. New equation is 39=3x. Finally divide. 39/3= 13.

You might be interested in

Find the length of line segmentAB which joins the following points.A(10, 14) and B(2,6)

Helen [10]

Answer:

The equation of the line AB is y - x -4 = 0

Step-by-step explanation:

The points are A (10,14) and B(2,6)

Now, slope of the line AB : $m = \frac{y_2 - y_1}{x_2 - x_1}$

or, $m = \frac{14 -6 }{10 - 2}$ = $\frac{8}{8} = 1$

So, slope of the equation AB = 1

Now, by SLOPE INTERCEPT FORM:

The equation of line is given as : y - y0 = m (x-x0)

So,the equation of line AB is y - 6 = 1(x-2)

or, y - 6 -x + 2 = 0

or, y - x -4 = 0

Hence, the equation of the line AB is y - x -4 = 0

5 0

3 years ago

When outliers are removed how does the mean change?

Juliette [100K]

The answer to this question is the mean increases by 3.

6 0

3 years ago

Read 2 more answers

What is the answer

Klio2033 [76]

Answer:

Step-by-step explanation:

Since 12 divided by 4 is 3, that is the constant. So 3 times 3 is 9

6 0

3 years ago

How can properties of operations help to generate equivalent expressions that can be used in solving problems ?

svet-max [94.6K]

I’m not the best at math, but ⬇️

For example, apply the distributive property to the expression 3(2 + x) to produce the equivalent expression 6 + 3x; apply the distributive property to the expression 24x + 18y to produce the equivalent expression 6 (4x + 3y); apply properties of operations to y + y + y to produce the equivalent expression 3y

6 0

4 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago