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Elina [12.6K]
2 years ago
13

Only one question, correct answer gets brainliest

Mathematics
2 answers:
hodyreva [135]2 years ago
7 0

Answer:

16.3420

Step-by-step explanation:

here is what I got

devlian [24]2 years ago
7 0

Answer:

CA ≈ 10 cm

Step-by-step explanation:

Since we know 2 sides and 1 angle we can use the Law of Cosine to find the third side.

CA = √(AB²+CB²- 2· AB· CB· cos 50°)

CA = √(7² +13² -2·7·13· cos 50°)

CA = √(49 +169 -116.987345)

CA = √101.012655

CA = 10.0505

CA ≈ 10 cm

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Find an equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
sattari [20]

Answer:

(x+5)^{2}=-4(y+3)

Step-by-step explanation:

Given:

Focus point = (-5, -4)

Vertex point = (-5, -3)

We need to find the equation for the parabola.

Solution:

Since the x-coordinates of the vertex and focus are the same,

so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.

The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.

Substitute y = -4 and k = -3.

-4 = -3+p

p=-4+3

p=-1

So the standard form of the parabola is written as.

(x-h)^{2}=4p(y-k)

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.

So the standard form of the parabola is written as.

(x-(-5))^{2}=4(-1)(y-(-3))

(x+5)^{2}=-4(y+3)

Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

(x+5)^{2}=-4(y+3)

7 0
3 years ago
Find the products of the following
user100 [1]

Step-by-step explanation:

4 0
3 years ago
Find the minimum cost of producing 60000 units of a product, where x is the number of units of labor, at $99 per unit, and y is
Y_Kistochka [10]

Answer:

The minimum cost of producing 60000 units of a product is $105867

Step-by-step explanation:

Since x is the number of units of labor, at $99 per unit, and y is the number of units of capital expended, at $84 per unit, The cost C(x,y) is given by:

C(x, y) = 99x + 84y

P(x, y) = 100x^{0.25}y^{0.75}

For the minimum cost:

100x^{0.25}y^{0.75}=60000\\x^{0.25}(\frac{33x}{28} )^{0.75}=600\\x^{0.25}(\frac{33}{28} )^{0.75}x^{0.75}=600\\x^{0.25+0.75}*1.131=600

Using the langrage multiplier,

99=0.25(100)x^{-0.75}y^{0.75}\lambda...(1\\84=0.25(100)x^{0.25}y^{-0.25}\lambda...(2

Dividing both equation 1 and 2

y=\frac{33}{28}x

Substituting y=\frac{33}{28}x in 100x^{0.25}y^{0.75}=60000, we get:

x_{min}=530.44 labor units

Substituting x_{min}=530.44  labor units in y=\frac{33}{28}x, we get

y_{min}=\frac{33}{28}*530.44=625.16 labor unit

C(x, y) = 99x + 84y=99(530.44)+84(635.16) = $105867\\

The minimum cost of producing 60000 units of a product is $105867

3 0
3 years ago
Allie and Joe are playing a game with a
umka2103 [35]

Answer: 0%

Step-by-step explanation:

There is no red on the spinner so there is a zero percent chance

5 0
3 years ago
For @apologiabiology
Lynna [10]
I think you are right but i am not sure
4 0
3 years ago
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