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3 years ago

A check is _____.

Mathematics

2 answers:

torisob [31]3 years ago

3 0

Answer:

Step-by-step explanation:

A check is an I.O.U. or a promissory note.

evablogger [386]3 years ago

3 0

Answer: B.) A promissory note

Step-by-step explanation: I've had this on a test before.

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If VZ=p–7 and WY=p–21, what is the value of p?

sveta [45]

Using the midline property;

$2wy = vz$

$2(p - 21) = p - 7$

$2p - 42 = p - 7$

$2p - p = - 7 + 42$

$p = 35$

8 0

2 years ago

(SUPER EASY) ILL GIVE BRAINLIEST TOO. <br><br><br> just answer all the questions you know.

wolverine [178]

Answer:

what is the question

Step-by-step explanation:

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3 years ago

A cone has a volume of 942 in.³ and a height of 9 inches what is the radius of the cone use 3.14 for pie

bija089 [108]

Answer:

r = 51.96 inches

Step-by-step explanation:

$V_{cone} = \pi {r}^{2} h \\ \\ \implies \: r^{2} = \frac{V_{cone}}{\pi h } \\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } }\\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } } \\ \\ \implies \: r^{2} =2700 \\ \\ \implies \: r= \sqrt{2700} \\ \\ \implies \: r=51.96 \: inches$

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2 years ago

There is a bag filled with 5 blue, 6 red and 2 green marbles.

Kipish [7]

Answer:

the probability of getting 2 greens is 2/13

Step-by-step explanation:

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3 years ago

A sales and marketing management magazine conducted a survey on salespeople cheating on their

Alenkinab [10]

Answer:

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In the survey on 200 managers, 58% of the managers have caught salespeople cheating on an expense report.

This means that $n = 200, \pi = 0.58$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.58 - 1.96\sqrt{\frac{0.58*0.42}{200}} = 0.5116$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.58 + 1.96\sqrt{\frac{0.58*0.42}{200}} = 0.6484$

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).

7 0

3 years ago