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3 years ago

How many perfect square are there between 1,000,000 and 9,000,000?

Mathematics

2 answers:

sp2606 [1]3 years ago

8 0

Answer: 1999 perfect squares between 1,000,000 and 9,000,00

Step-by-step explanation:

Sq root of 1,000,000 is 1000 and square root of 9,000,000 is 3000

Hence there are squares of 1001 to 2999 I. e. 1999 perfect squares between 1,000,000 and 9,000,00

Usimov [2.4K]3 years ago

7 0

Answer:

1999

Step-by-step explanation:

The square root of 1,000,000 = 1,000.

The square root of 9,000,000 = 3,000.

This means that the number of perfect square will be every number from 1,000^2 to 3,000^2. To find how many numbers that is, just do 3000-1000 = 2000, and then subtract one because otherwise you would be counting the 3000^2 which you don't want to do (it asks how many perfect squares are between the two numbers).

2000 - 1 = 1999.

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A circle has the equation x2 + (y−7)2 = 121. What is the length of the diameter of the circle?

Reika [66]

Answer:

Step-by-step explanation:

The standard form for an equation of a circle is $(x-h)^2+(y-k)^2=r^2$ , where h is the x coordinate of the center of the circle, k is the y coordinate, and r is the radius of the circle. Therefore, the radius of this circle squared is 121, meaning that the radius of the circle is 11. Since the diameter of a circle is twice the radius, the radius of this circle is 22. Hope this helps!

8 0

3 years ago

enelope determined the solutions of the quadratic function by completing the square. f(x) = 4x2 + 8x + 1 –1 = 4x2 + 8x –1 = 4(x2

Marat540 [252]

The correct question is
<span>Penelope determined the solutions of the quadratic function by completing the square.
f(x) = 4x² + 8x + 1
–1 = 4x² + 8x
–1 = 4(x² + 2x)
–1 + 1 = 4(x² + 2x + 1)
0 = 4(x + 2)²
0 = (x + 2)²
0 = x + 2
–2 = x
What error did Penelope make in her work?

we have that
</span>f(x) = 4x² + 8x + 1
to find the solutions of the quadratic function
let
f(x)=0
4x² + 8x + 1=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(4x² + 8x)=-1

Factor the leading coefficient

4*(x² + 2x)=-1

Complete the square Remember to balance the equation by adding the same constants to each side.

4*(x² + 2x+1)=-1+4 --------> ( added 4 to both sides)

Rewrite as perfect squares

4*(x+1)²=3

(x+1)²=3/4--------> (+/-)[x+1]=√3/2

(+)[x+1]=√3/2---> x1=(√3/2)-1----> x1=(√3-2)/2

(-)[x+1]=√3/2----> x2=(-2-√3)/2

therefore

the answer is

<span>Penelope should have added 4 to both sides instead of adding 1.</span>

6 0

4 years ago

Read 2 more answers

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$