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aleksklad [387]
2 years ago
8

If a car is worth 28,000 in 2019 and the value depreciates at8.5% per year, what will it be worth in 2030? The answer is 10,538.

77 I just need help finding how to get that answer.
Mathematics
1 answer:
ra1l [238]2 years ago
5 0

Answer:

Step-by-step explanation:

just take 8.5% of 28,020 off for ever year until you get to 2030.

8.5% is 2381.70

Take 2381.70 of 28,020 each year

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What is the slope of a line parallel to the line containing (-6,1) and (3,-2)
timama [110]

Answer:

m = -\frac{3}{9}

Step-by-step explanation:

Use the following formula:

slope: m = (y_{2} - y_{1})/(x_{2} - x_{1})

Let:

(x_{1} , y_{1}) = (-6 , 1)\\ (x_{2} , y_ {2}) = (3 , -2)\\

Plug in the corresponding numbers to the corresponding variables:

m = \frac{-2 - 1}{3 - (-6)}\\\\m = \frac{-3}{3 + 6}\\\\m = \frac{-3}{9}

m = -\frac{3}{9} is your answer.

~

3 0
3 years ago
One of the formulas for calculating the correct dosage for a child is as follows: C= a/((a+12)) ∙ 180 C = child’s dosage in mill
bogdanovich [222]
So you already have the formula for calculating the dosage for child with: C = a/(a+12)x 180 ml Not sure why you have double brackets

variables are: a = child's age, so everywhere you have an "a" replace it with the age of child.

Example: 5 year old child

C = 5/(5+12)*180= 5/(17)*180 = 5/3060 = .0016 ml or milligrams
8 0
3 years ago
Si a un múltiplo de 8 le sumo 1 obtengo un múltiplo de 5, ¿qué múltiplos de 8
Simora [160]

Answer:

24, 64

Step-by-step explanation:

If I add 1 to a multiple of 8 I get a multiple of 5, what multiples of 8

meet the condition? (Mention at least 2 of them)

3 x 8 + 1 = 25

8 x 8 + 1 = 65

4 0
2 years ago
A company has a budget of $280,000 for computing equipment. Tablets cost $500 each, laptops cost $2000 each, and servers cost $5
Kazeer [188]

Answer:

The number of tablets  200

the number of laptops  40

and, the number of servers 20

Step-by-step explanation:

Let the number of tablets be 'x'

the number of laptops be 'y'

and, the number of servers be 'z'

According to the given question

Total budget = $280,000

Tablets cost = $500 each

laptops cost = $2000 each

servers cost = $5000 each

Thus,

500x + 2000y + 5000z = 280,000 ..............(1)

also,

x = 5y  ................(2)

and,

y = 2z  

or

z = \frac{\textup{y}}{\textup{2}}   ............(3)

substituting y from 2 and 3 in equation 1,  we get

(500 × 5y) + (2000 × y) + (5000 × \frac{\textup{y}}{\textup{2}} ) = 280,000

or

2500y + 2000y + 2500y = 280,000

or

7000y = 280,000

or

y = 40

substituting y in equation 2, we get

x = 5 × 40 = 200

substituting y in equation 3 we get

z = \frac{\textup{40}}{\textup{2}}

or

z = 20

hence,

the number of tablets  200

the number of laptops  40

and, the number of servers 20

7 0
3 years ago
HELP!!!!!!!!!!! !!!!!!!!!!
Sonja [21]

Answer:

second one is 3, the last one is 4560

Step-by-step explanation:

5 0
2 years ago
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