Area of the three equally sized stripes: A
A=(x+15)(x)(3)
A=3x(x+15)
A=3x^2+45x
One gallon of paint will cover an area of no more than 400 square feet: <=400
She only has half of a gallon of paint left:
1/2(400 square feet)=400/2=200 square feet
Inequality that could be used to find the maximum height, in feet, of each stripe:
A<=200
3x^2+45x<=200
Answer: 3x^2+45x <= 200
Could her stripes be 3' tall?
x=3→A=3(3)^2+45(3)=3(9)+135=27+135→A=162<200 Ok
Yes, her stripes could be 3' tall.
Answer: Yes
Could her stripes be 4' tall?
x=4→A=3(4)^2+45(4)=3(16)+180=48+180→A=228>200 No
No, her stripes couldn't be 4' tall.
Answer: No
The answer would be O x=39
Es 1/2 . 30+20= 50
50/100 = 1/2
porfa dame brilliant answer
Equation 1 + equation 2
3x-8y +(-3x+10y) = 9+(-15)
2y= -6
then y=-3
from equation 1
3x-8y=9
3x-8(-3)=9
3x+24=9
3x=9-24=-15
then x=-5
