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meriva
3 years ago
10

When solving the following system of equations, which variable would be the easiest to solve for? 5x + 3y = 22 4x – 2y = 16 O th

e y in the second equation o the y in the first equation the x in the second equation O the x in the first equation​
Mathematics
1 answer:
Sav [38]3 years ago
6 0

Answer:

What you need to do is get of that lazy bum of yours and do it your self

Step-by-step explanation:

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anygoal [31]

Answer:

Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team

Step-by-step explanation:

For each snacks Lucas uses one cup of dried cherries and 2 cup of dried apricots. One dozen of snack  contains a total of 12 snacks. Therefore to prepare 12 snacks (one dozen) the number of dried cherries and dried apricots can be gotten by multiplying the number of dried cherries and dried apricots required for each snack by 12.

Number of dried cherries = 1 cup for each snack × 12 snacks = 12 cups

Number of dried apricots = 2 cup for each snack × 12 snacks = 24 cups

Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team

3 0
3 years ago
Use conversions to solve the problem. Devante buys 1 1/2
melomori [17]

Answer:

45 oz

Step-by-step explanation:

1.5 lb = 24 oz

3/4 = 12 oz

24+12+9 = 45 oz

6 0
3 years ago
WILL GIVE BRAINLEST plz help meeeeeeeee
mixer [17]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, 62% of graduate
egoroff_w [7]

Answer:

    \frac{31}{50}

Step-by-step explanation:

percentage of graduates with loan = 62%

total sample = 50

Number of student in the sample with student loan

  = (percentage of graduates with loan) x  (total sample)

  = 62% x 50

  = 31

Proportion of student in the sample with student loan = \frac{31}{50}

4 0
3 years ago
How are dilations and functions related?
Anika [276]
If we dialate a function we are just changing what the graph looks like by a stretch or a compression, the function really doesn't change.  If a function before the dilation, then it is a function after the dilation.  The opposite is also true.
5 0
3 years ago
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