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meriva
3 years ago
10

When solving the following system of equations, which variable would be the easiest to solve for? 5x + 3y = 22 4x – 2y = 16 O th

e y in the second equation o the y in the first equation the x in the second equation O the x in the first equation​
Mathematics
1 answer:
Sav [38]3 years ago
6 0

Answer:

What you need to do is get of that lazy bum of yours and do it your self

Step-by-step explanation:

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Circle O has a circumference of 36tt cm. what is length of the radius r
allochka39001 [22]

Answer:

5.73cm

Step-by-step explanation:

Given parameters:

Circumference of the circle = 36cm

Unknown

Length of the radius = ?

Lets represent the radius by r

Solution

The circumference of a circle is the defined as the perimeter of a circle. The formula is given as:

            Circumference of a circle = 2πr

Since the unknown is r, we make it the subject of the formula:

           r = \frac{circumference of the circle}{2π}

          r = \frac{36}{2 x 3.142} = \frac{36}{6.284} = 5.73cm

3 0
3 years ago
Read 2 more answers
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
Simplify: 3(a-2)+4(3-a)-10
Neporo4naja [7]

Answer:

-a - 4

Step-by-step explanation:

3(a-2)+4(3-a)-10

3a - 6 + 12 - 4a - 10

-a - 4

3 0
3 years ago
What is the value of q in the equation 5q − 10 = 75?
Kamila [148]

Answer:

should be 17

Step-by-step explanation:

5 0
2 years ago
Wes had 4.75 in quarters and dimes if he had 25 coins how many of each did he have?
Verizon [17]

Answer:it would be 15 quarters and 10 dimes

Step-by-step explanation:

15 quarters is 3.75 and 10 dimes is $1, add them up you get $ 4.75

5 0
3 years ago
Read 2 more answers
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