Answer:
You should have:
a vertex at (1,8)
a y-intercept at (0,6)
a parabola that opens down
and x-intercepts of (-1,0) and (3,0)
Step-by-step explanation:
To get the vertex, you take the number inside the square (h value) and invert the sign for the x value then take the value on the end (k value) and make that the y. For the y-intercept if you let x=0 then the value you get will be the y value at which the graph hits the axis. For the direction in which the parabola opens if the number in front of the square ((x-h)^2 ) is negative it opens down and if it is positive it opens up. For the x-intercepts if you put either number into the function you will get 0.
Answer:
s
Step-by-step explanation:
5.5~
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Answer
5.0/5
7
oeerivona
Answer:
The value of x is 9°
Step-by-step explanation:
The given parameters are;
ΔUVW with side UW extended to X
m∠UVW = (3x + 4)°
m∠VWX = (8x -12)°
m∠WUV = (x + 20)°
We have that m∠UVW + m∠WUV + m∠VWU = 180° (Sum of the interior angles of a triangle theorem)
∴ m∠VWU = 180° - (m∠UVW + m∠WUV)
Also we have that m∠VWX and m∠VWU are supplementary angles, (The sum of angles on a straight line)
∴ m∠VWX + m∠VWU = 180° (Definition of supplementary angles)
m∠VWU = 180° - m∠VWX
∴ m∠VWX = (m∠UVW + m∠WUV)
Substituting the values, gives;
(8x -12)° = (3x + 4)° + (x + 20)°
8x - 3x - x = 4 + 20 + 12
4x = 36
x = 36/4 = 9
x = 9°.
