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ladessa [460]
2 years ago
8

PLEASE HELP MEE!!! I WILL GIVE YOU THE BRAINLIEST

Mathematics
1 answer:
True [87]2 years ago
5 0

Answer:

Domain (-infinity, infinity) Range (-4, infinity)

Step-by-step explanation:

look at the x axis. the graph is going forever out, so infinity.

now look at the y axis. where does it stop? -4. you might need to use [ instead of ( when answering your problem (that just means including) hope this helps!

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How to find pattern and equation of y = 3x + 7
ruslelena [56]

Answer:

Use desmos.

Step-by-step explanation:

In the image attached, I graphed the linear function on a graphing calculator. B=7 and the slope is 3.

7 0
3 years ago
I will give brainliest if correct!!! Please show work so I know how to do it. :)
yawa3891 [41]

Answer:

.2625

Step-by-step explanation:

logb(3) = 0.5646, logb(4) = 0.7124, and logb(5) = 0.8271

logb(5/3)

We know that logx ( y/z) = logx (y) - logz (z)

logb ( 5) - logb(3)

0.8271 - 0.5646

.2625

5 0
3 years ago
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According to a study, 91% of all adults have a cell phone. An employee of a cell phone company attends a community event and has
umka2103 [35]

Answer:

(0.91)^{20}(0.09)

Step-by-step explanation:

6 0
3 years ago
What is the equation of this graphed line ?
yanalaym [24]
Equations of straight lines are in the form y = mx + c (m and c are numbers). m is the gradient of the line and c is the y-intercept (where the graph crosses the y-axis).
7 0
3 years ago
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NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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