You're just a step away from the equation of the line that's perpendicular to [ y = 5/6 x + 7 ]. ... You know that its slope is -6/5 and that it contains the point (3, 2). ... Find the equation of that line. Then find the point where the two lines intersect. Then find the distance between that point and (3, 2). SIR !
Answer:
x = 14/3 + sqrt(217)/3 or x = 14/3 - sqrt(217)/3
Step-by-step explanation:
Solve for x:
x + 4 + 1/x = (10 x)/7
Bring x + 4 + 1/x together using the common denominator x:
(x^2 + 4 x + 1)/x = (10 x)/7
Cross multiply:
7 (x^2 + 4 x + 1) = 10 x^2
Expand out terms of the left hand side:
7 x^2 + 28 x + 7 = 10 x^2
Subtract 10 x^2 from both sides:
-3 x^2 + 28 x + 7 = 0
Divide both sides by -3:
x^2 - (28 x)/3 - 7/3 = 0
Add 7/3 to both sides:
x^2 - (28 x)/3 = 7/3
Add 196/9 to both sides:
x^2 - (28 x)/3 + 196/9 = 217/9
Write the left hand side as a square:
(x - 14/3)^2 = 217/9
Take the square root of both sides:
x - 14/3 = sqrt(217)/3 or x - 14/3 = -sqrt(217)/3
Add 14/3 to both sides:
x = 14/3 + sqrt(217)/3 or x - 14/3 = -sqrt(217)/3
Add 14/3 to both sides:
Answer: x = 14/3 + sqrt(217)/3 or x = 14/3 - sqrt(217)/3
Answer:
25
Step-by-step explanation:
did the question
The distance Jada is from starting point will be found using the cosine formula:
c²=a²+b²-2abCos C
a=200, b=90, C=70°
thus plugging in our values we get:
c²=200²+90²-2×200×90×cos70
c²=40000+8100-36000(0.3420)
c²=35788
hence
c=189.1772 m'
therefore the distance Jada is from the starting point is 189.1772 m
