Question

A number cube is rolled twice. What is the P (2 and then odd number)?

Answer 1

Answer:

P (2 and then odd number) = $\frac{1}{12}$

Step-by-step explanation:

Probability refers to chances of occurrence of any event.

A number cube is rolled twice.

Possible outcomes are as follows:

$(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)$

$(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)$

$(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)$

$(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)$

$(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)$

$(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)$

Total number of outcomes = 36

Favorable outcomes include outcomes with 2 and then odd number.

So,

Favorable outcomes are $(2,1),(2,3),(2,5)$

Number of favorable outcomes = 3

Probability is equal to number of favorable outcomes divided by total number of outcomes.

Therefore,

P (2 and then odd number) = Number of favorable outcomes ÷ Total number of outcomes

$=\frac{3}{36}$

$=\frac{1}{12}$