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exis [7]
3 years ago
8

Write a rule for the sequence. then, find the unknown term 2.1, 4.3, 6.5, ..., 10.9

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer

8.7

All the first digits are even numbers..and the numbers behind the decimal points are odd numbers

malfutka [58]3 years ago
3 0

Answer:

8.7

Step-by-step explanation:

I'm assuming you want the term between 6.5 and 10.9

The sequence is aritmetic with a

common difference of 6.5 - 1.3 = 4.3 - 2.1 = 2.2

6.5 + 2.2 = 8.7

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Natasha2012 [34]

Answer:

There are 2 solutions:

X=-7.5

X=4.5

**The positive one is 4.5** so it should be that

Step-by-step explanation:

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3 years ago
I need help in this. Please
Ipatiy [6.2K]

Answer:

search it up :)

Step-by-step explanation:

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Expand (x-3)(x-8) to form a quadratic expression
AlladinOne [14]

Answer:

x^2 - 11x + 24

Step-by-step explanation:

Foil the equation

x^2 - 3x - 8x + 24

x^2 - 11x + 24

8 0
3 years ago
El conjunto de 10 centenas de mil es igual a _________ unidades El conjunto de 10 decenas de mil es igual a __________ unidades
Tanya [424]

Answer:

<u>10 centenas de mil =  1000.000 unidades.</u>

Step-by-step explanation:

Recordemos que <u>10 centenas es igual a 1000 unidades</u>

Ahora, 10 centenas de mil seria un millon de unidades

Osea, <u>1000.000 unidades.</u>

Espero te haya servido.

8 0
3 years ago
The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

7 0
3 years ago
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