Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Answer:
-5.1x + 12.3
Step-by-step explanation:
Combine like terms: first, combine the x terms, obtaining -5.1x.
Next, combine the constants, obtaining 12.3.
The simplified expression is -5.1x + 12.3
I’m pretty sure the answer is A I hope that helps :)
There is only solutions to the systems of equations - y = x -2 & y = -x + 2. We can find this by looking at the slopes of each line, which is 1 and -1. They are not negative reciprocals or the same exact slope, which would give the system of equations no solutions. Since the lines are not exactly the same, the system does not have infinitely many solutions. A system of LINEAR equations cannot have two solutions, giving us an answer of only one solution. Hope this helps!
Answer:
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