To solve this problem,you need to use the formula d = rd (distance = rates x time)She runs at a speed of 7 mph and walks at a speed of 3 mph. Her distance running is d = 7trwhere tr is the time she spends running Her distance walking isd = 3twwhere tw is the time she spends walking The distances are the same so7tr = 3tw We also know that the total time is 4 hourstr + tw = 4tr = 4-tw Substitute this value of tr in the first equation7tr = 3tw7(4-tw) = 3tw28-7tw = 3tw28 = 10tw2.8 = tw Denise will spend 2.8 hours (2 hours, 48 minutes) walking back and 1.2 hours (1 hour, 12 minutes running.
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The answer is A.
If the submarine descended then it went below, and if it ascended it went above. Therefore:
"Descended 2 miles"= -2
"Then descended another 3 miles"= -3
(-2)+(-3)=-5
Adding two negatives together will give you a bigger negative so the submarine would then be 5 miles below its original location.
Answer:
D) 4x + 5y = -30 = -4/5
Step-by-step explanation:
A) 5x + 4y = 28 slope = -5/4
b) 4x-5y = -25 slope = 4/5
c) 4y - 5x = -12 slope = 5/4
d) 4x + 5y = -30 slope = -4/5
Put this in your calculator or use pictures if you'd like. (3/4) x 12 and you'll get 9
