Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
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Explanation:</h2><h2>
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Here we need to simplify the square root of ten times square root of eight, so let's write this step by step:
Step 1. The square root of ten
Step 2. The square root of eight
Step 3. The square root of ten times square root of eight
Finally, the correct option is:
<em>Four square root of five</em>
Li needs 3 more pieces, an 1 and 1/2 cut into 3 pieces.
Answer:
f^-1(x) = (x+20) / 12
Step-by-step explanation:
f(x) = 4(3x-5)
Let y be the image of f.
y = 4(3x-5)
y = 12x-20
y+20 = 12x
x = (y+20) / 12
f^-1(y) = (y+20) / 12, so
f^-1(x) = (x+20) / 12
Answer:
316 eggs were spoiled.
Step-by-step explanation:
1020304 / 348 = 2931 remainder 316.
