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devlian [24]
3 years ago
15

Determine the critical value for a 98% confidence interval when the sample size is 12 for the t ‑distribution. Enter the positiv

e critical value rounded to 3 decimal places.
Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

+2.718

Step-by-step explanation:

from the question,

the sample size is 12

therefore the degree of freedom,

df = 12 - 1

= 11

alpha = 1 - 0.98

= 0.02

this is because the confidence level is 98%

under the t distribution table, a degree of freedom of 11 and 0.02 alpha level = <em>2.718</em>

<em>the</em><em> </em><em>crit</em><em>ical</em><em> </em><em>valu</em><em>e</em><em> </em><em>t</em><em>*</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>7</em><em>1</em><em>8</em>

<em>I </em><em>hop</em><em>e</em><em> </em><em>th</em><em>is</em><em> </em><em>helps</em><em>!</em>

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