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3 years ago

13

Find the first 5 terms in the sequence an = 2n - 1

1 answer:

JulsSmile [24]3 years ago

5 0

Answer:

1, 3, 5, 7, 9

Step-by-step explanation:

$a_n = 2n - 1$

n = 1:

$a_1 = 2(1) - 1 = 2 - 1 = 1$

n = 2:

$a_2 = 2(2) - 1 = 4 - 1 = 3$

n = 3:

$a_3 = 2(3) - 1 = 6 - 1 = 5$

n = 4:

$a_4 = 2(4) - 1 = 8 - 1 = 7$

n = 5:

$a_5 = 2(5) - 1 = 10 - 1 = 9$

Answer: 1, 3, 5, 7, 9

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Estimate how many times larger 4 x 10^15 is than 8 x 10^9 in the form of a single digit times an integer power of 10.

netineya [11]

Answer:

5×10⁵

5×10⁶

Step-by-step explanation:

1)

$\dfrac{4\cdot 10^{15}}{8\cdot 10^{9}}=\dfrac{40\cdot 10^{14}}{8\cdot 10^{9}}\\\\=\dfrac{40}{8}\cdot 10^{(14-9)}=5\cdot 10^{5}$

2)

$\dfrac{2\cdot 10^{-5}}{4\cdot 10^{-12}}=\dfrac{20\cdot 10^{-6}}{4\cdot 10^{-12}}\\\\=\dfrac{20}{4}\cdot 10^{(-6-(-12))}=5\cdot 10^{6}$

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The angle created by ray OX and ray OZ is angle . The two rays that create YOX are ray OX and ray . The center of the circle is

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1. XOZ

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3 years ago

Read 2 more answers

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

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3 years ago

If 15% of 4x is 20 less than x, what is the value of x?

Bess [88]

The sentence "15% of 4x is 20 less than x"

translates to 0.15 • (4x) = x – 20

Solving that…

0.15(4x) = x - 20 multiplipy 0.15•4

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-0.4x = - 20 divide both sides by -0.4

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