Pls, help with this question
1 answer:
Answer:
Step-by-step explanation:
Arc BC is the intercepted arc for the central angle COB, so its measure is the <u>same</u> as the central angle.
Angle 2 is an inscribed angle, so its measure is <u>half</u> the measure of the intercepted arc BC.
Angles 3 and 4 are congruent inside an isosceles triangle (OB = OC, both radii), and the sum of all angles in triangle COB is 180 degrees, so
180 - 32 = 148 (sum of angles 3 and 4)
Each of angles 3 and 4 measure half that remaining 148 degrees.
Angle 5 is one of two congruent angles in an isosceles triangle AOC (OA = OC) so its measure is that of angle 2.
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Answer:
10 number of checks.
Cost = $6
Step-by-step explanation:
Given that:
Fixed Charges of first bank = $5
Charges of first bank per check = $0.10
Fixed Charges of second bank = $4
Charges of second bank per check = $0.20
To find:
Number of checks such that the charges for the banks become the same?
Solution:
Let the number of checks =
Cost for the first bank for checks = $5 + $0.10
Cost for the second bank for checks = $4 + $0.20
As per question statement, both the costs are the same.
Comparing the values:
So, for 10 number of checks the cost will be same.
The cost = 4 + 0.20 10 = <em>$6</em>
Answer:
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
m∠RPS= ------> external angle
so
m∠RPS=
we have
m∠RPS=
substitute the values
Solve for arc RS
Answer: y=
s=-30+10t
Step-by-step explanation:
9x + 2y = 5; y
9x-9x+2y = 5-9x
2y=5-9x
y=
1/15s - 2/3t = -2; s
(1/15s - 2/3t = -2)*15 ==> Get rid of fraction by multiplying both sides by 15
s - 30/3 t=-30
s-10t=-30
s=-30+10t