Question

Pls, help with this question

Answer 1

Answer:

$m\text{ arc BC} =32\\m\angle 2=16\\m\angle3=74\\m\angle4=74\\m\angle5=16$

Step-by-step explanation:

Arc BC is the intercepted arc for the central angle COB, so its measure is the same as the central angle.

Angle 2 is an inscribed angle, so its measure is half the measure of the intercepted arc BC.

Angles 3 and 4 are congruent inside an isosceles triangle (OB = OC, both radii), and the sum of all angles in triangle COB is 180 degrees, so

180 - 32 = 148 (sum of angles 3 and 4)

Each of angles 3 and 4 measure half that remaining 148 degrees.

Angle 5 is one of two congruent angles in an isosceles triangle AOC (OA = OC) so its measure is that of angle 2.