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dmitriy555 [2]
2 years ago
14

I need help with aleks

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
4 0

Answer:

All angles are equal because all sided are equal so the 1st 1 is 60 .

the 2nd is 80

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What is 4x(3/5)+(3-98)=
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It would be 2.4x+(-95)=
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3 years ago
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EXPLAIN THE ERROR Cody was given two points (1/2,4) and (2/3,1), on a line and asked to create a linear equation in standard for
inessss [21]

Answer:

Cody made a mistake when calculating the slope of the line and this affected every other steps after than.

She divided -3 by 6 instead of -3 by 1/6

Step-by-step explanation:

Given

(x_1,y_1) = (\frac{1}{2},4)

(x_2,y_2) = (\frac{2}{3},1)

<em>See attached for steps</em>

Required

Explain Cody's error

<em>Cody made a mistake when calculating the slope of the line and this affected every other steps after than.</em>

See Proof

Slope (m) is calculated as thus:

m =\frac{y_2 - y_1}{x_2 - x_1}

m =\frac{1 - 4}{\frac{2}{3} - \frac{1}{2}}

m =-\frac{ 3}{\frac{1}{6}}

m = -3/\frac{1}{6}

m = -3 * 6

m = -18

This is in contrast to m = -\frac{1}{2}, calculated by Cody

Solving further to determine the equation.

y - y_1 = m(x - x_1)

Where

(x_1,y_1) = (\frac{1}{2},4)

m = -18

y - 4 = -18(x - \frac{1}{2})

y - 4 = -18x + 9

Collect Like Terms

y + 18x = 9 + 4

y + 18x = 13

6 0
3 years ago
How to do HCF and LCM
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To find the GCF, list the prime factors of each number, then multiply the factors that both number have in common. To find the LCD, find the smallest possible integer divisible by both numbers.
7 0
3 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

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