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3 years ago

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What is the value of x? x = ?

2 answers:

meriva3 years ago

8 0

<em> </em><em>Sum </em><em>of </em><em>both </em><em>the </em><em>angle </em><em>will </em><em> </em><em>1</em><em>8</em><em>0</em><em> </em><em>because</em><em> of</em><em> </em><em>linear </em><em>pair</em>

now, <em>1</em><em>0</em><em>x</em><em> </em><em>-</em><em> </em><em>2</em><em>0</em><em> </em><em>+</em><em> </em><em>6</em><em>x</em><em> </em><em>+</em><em> </em><em>8</em><em> </em><em> </em><em>=</em><em>. </em><em>1</em><em>8</em><em>0</em><em> </em>

<em> </em><em> </em><em>1</em><em>6</em><em>x</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em>

<em>1</em><em>6</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>9</em><em>2</em><em> </em>

<em>x=</em><em> </em><em>1</em><em>9</em><em>2</em><em>/</em><em>1</em><em>6</em>

<em>x </em><em>=</em><em> </em><em>1</em><em>2</em>

<em>1</em><em>s</em><em>t</em><em> </em><em>angle </em><em>=</em><em> </em><em>1</em><em>0</em><em>0</em>

<em>2</em><em>n</em><em>d</em><em> </em><em>is </em><em>=</em><em> </em><em>8</em><em>0</em>

<em>Hope</em><em> it</em><em> helps</em><em> and</em><em> your</em><em> day</em><em> will</em><em> full</em><em> of</em><em> happiness</em>

prohojiy [21]3 years ago

4 0

The value of x 180 is your answer

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A building's basement is 12 feet below ground. If the total length of the building from basement to roof is 62 feet, what is the

Effectus [21]

Answer:

62-12=50

Step-by-step explanation:

hope that helps!

5 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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