The surface area of a cylinder with circular bases of radius <em>r</em> and height <em>h</em> is equal to the sum of the areas of the two circular faces and the area of the rectangular lateral surface:
<em>A</em> = 2π<em>r</em>² + 2π<em>rh</em>
If you know the height <em>h</em>, then you can solve the quadratic equation for <em>r</em>.
electricity comes from electrons, does morality come from morons? No, you're thinking of mormality. That is true, especially in the US. ... This means that the stupider a group is overall, the less moral they are expected to beon:
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Standard equation of circle is :
Since the circle is centered at origin, h = k = 0
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Vectors are elements of the vector space, and they can be illustrated by diagrams.
<h3>How to draw the vector 2u - 1/3v</h3>
The vector expression is given as:
2u - 1/3 v
Split the vector expressions, as follows:
See attachment for the graphs of y1 and y2.
Next, we have:
So, we have:
The above expression means that, we add the vectors y1 and y2 to get vector y
See attachment for the graph of 2u - 1/3 v
Read more about vectors at:
brainly.com/question/14480278
Answer:
The company should make 0 jumbo and 300 regular biscuits.
The maximum income is $42.
Step-by-step explanation:
Let's say J is the number of jumbo biscuits and R is the number of regular biscuits.
The oven can bake at most 300 biscuits. So:
J + R ≤ 300
Each jumbo biscuit uses 2 oz of flour, and each regular biscuit uses 1 oz of flour. There is 500 oz of flour available. Therefore:
2J + R ≤ 500
Income from jumbo biscuits is $0.12, and income from regular biscuits is $0.14. So the total income is:
I = 0.12J + 0.14R
Graph the two inequalities under the condition that J ≥ 0 and R ≥ 0:
desmos.com/calculator/aea00cmpwm
The region where the inequalities intersect has 4 corners:
(J, R) = (0, 0); (0, 300); (250, 0); (200, 100)
Find the income at each point:
(0, 0): I = 0
(0, 300): I = 42
(250, 0): I = 30
(200, 100): I = 38
The company makes maximum profit of $42 by baking 0 jumbo biscuits and 300 regular biscuits.
