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2 years ago

Math hw plz help! ill give brainliest

Mathematics

2 answers:

Debora [2.8K]2 years ago

5 0

You need to add an image

zhenek [66]2 years ago

4 0

Answer:

what is the question?

???

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Miguel volunteers at his local food pantry and takes note of how much money is donated each day during a 10-day fundraising phon

tangare [24]

Answer:bbb

Step-by-step explanation:

4 0

3 years ago

The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given

o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

$D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80$

Reorganize the terms in one side and reduce similar terms:

$3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0$

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

$q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10$

q can't be negative because it is the quantity of bike frames, so:

$q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\$

This value of q can't be considered.

Then substitute the value of q in D(q) to find the price p:

$D(10) = -6.10(10)^2-5(10) + 1000\\\\D(10)=340=p$

The equilibrium point (q,p) is (10,340).

6 0

3 years ago

(4x-4) (3x+17) The lines. intersect at point C. What is the value of X?

Marina86 [1]

Answer:

(21, 80)

Step-by-step explanation:

We have the two lines y = 4x -4 and y = 3x + 17. The point 'C' will be given by the interception of them, as follows:

4x -4 = 3x + 17

Solving for 'x':

x = 21

Now, to find 'y' we have:

y = 4(21) -4 = 80

Therefore, they intercept at: (21, 80)

7 0

3 years ago

Read 2 more answers

Ian picked 5 times as many strawberries as Michelle. Joe picked 7 times as many strawberries as Michelle. Ian and Joe picked a t

Crazy boy [7]

Answer:

Joe picked 112 strawberries

Step-by-step explanation:

If Ian picked 5 times as many strawberries as Michelle, and Joe picked 7 times as many as Michelle. Together, Ian and Joe picked a total 192 strawberries.

If we want to find out how many strawberries Joe picked, we need to work with the proportions we are given.

Let's denote Michelle's strawberries as x

Ian picked five times that many: 5x

Joe picked 7 times that many: 7x

Ian and Joe together picked 192 strawberries

192 = 5x + 7x combine like terms

192 = 12x divide both sides by 12 to isolate x

x = 16

If Joe's strawberries are represented by 7x and x is 16 strawberries, then

7 (16) = Joe's strawberries

Joe picked 112 strawberries

7 0