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lana66690 [7]
3 years ago
14

Math hw plz help! ill give brainliest

Mathematics
2 answers:
Debora [2.8K]3 years ago
5 0
You need to add an image
zhenek [66]3 years ago
4 0

Answer:

what is the question?

???

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Gwar [14]

the Answer is c. I think

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3 years ago
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Usain Bolt ran the 2012 Olympic 100-meter race in 9.63 seconds. If he runs at this rate on a road with a speed limit of 25 miles
djverab [1.8K]

Answer:

3874.5342

Step-by-step explanation:

9.63 divide by 100 = 0.0963

0.0963x40 234= 3874.5342

6 0
3 years ago
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Suppose a new car is purchased for $46,357 and depreciates by 22% over the first year of ownership. If the car is driven 12,170
miss Akunina [59]

Answer:check the pic

Step-by-step explanation:

3 0
3 years ago
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- Write a recursive formula to represent the sequence below.<br> (3,7, 11, 15, 19,23,27,31,35, ...)
NemiM [27]

<em><u>The recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n  = 1, 2, 3, ....

<em><u>Solution:</u></em>

Given a sequence is:

3, 7, 11, 15, 19, 23, 27, 31, 35

<em><u>Let us find the difference between terms</u></em>

7 - 3 = 4

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

23 - 19 = 4

27 - 23 = 4

31 - 27 = 4

35 - 31 = 4

Thus the difference between terms is constant

Thus the given sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

<em><u>The nth term of arithmetic sequence is given by:</u></em>

a_n =a_1+(n-1)d

a_n = the nᵗʰ term in the sequence

a_1 = the first term in the sequence

d = the common difference between terms

Here in the given sequence

d = 4

a_1=3

Substitute in above formula,

a_n = 3 + (n-1)(4)\\\\a_n = 3 + 4n - 4\\\\a_n = 4n - 1

<em><u>Thus the recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n = 1, 2, 3, ......

8 0
3 years ago
Which properties are present in a table that represents an exponential function in the form y-b* when b &gt; 1?
erastovalidia [21]

Answer:

<u>Properties that are present are </u>

Property I

Property IV

Step-by-step explanation:

The function given is  y=b^x  where b > 1

Let's take a function, for example,  y=2^x

Let's check the conditions:

I. As the x-values increase, the y-values increase.

Let's put some values:

y = 2 ^ 1

y = 2

and

y = 2 ^ 2

y = 4

So this is TRUE.

II. The point (1,0) exists in the table.

Let's put 1 into x and see if it gives us 0

y = 2 ^ 1

y = 2

So this is FALSE.

III. As the x-value increase, the y-value decrease.

We have already seen that as x increase, y also increase in part I.

So this is FALSE.

IV. as the x value decrease the y values decrease approaching a singular value.

THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.

This is TRUE.

Option I and Option IV are true.

3 0
3 years ago
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