Answer:
The slope will be 0
Step-by-step explanation:
Once you do the slope formula which is y2 - y1 over x2-x1
You will get 0/3 in this case. So if the numerator is a 0 the slope will also be 0.
Step-by-step explanation:
sin(x) = 1
cos(x) = 0
tan (x) = <u>sin(x)</u>
cos(x)
tan(x) = 1/ 0
Which can be considered as undefined or infinite
2b 2a
----------------- + -----------------
(b+a)^2 (b^2 - a^2)
2b 2a
= ----------------- + -------------------
(b+a)(b+a) (b+a)(b-a)
2b(b - a) + 2a(b + a)
= ------------------------------------
(b+a)(b+a)(b-a)
2b^2 - 2ab + 2ab + 2a^2
= ---------------------------------------
(b+a)(b+a)(b-a)
2b^2 + 2a^2
= ------------------------
(b+a)(b+a)(b-a)
2(b^2 + a^2)
= ------------------------
(b+a)^2 (b-a)
Answer:
Numerator: 2(b^2 + a^2)
Denominator: (b+a)^2 (b-a)
The answer is B.
I tried putting 9 for a and 7 for B. cos(9-7)+cos(9+7) = 2cos(9)cos(7)
