Question 4
1 answer:
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<span>The answer is 500 miles.
</span>
So how you go about this problem is to first write an equation for how much each company will cost.
For Company A, it costs $120 plus some more.
The some more part can just be written as .4x where x is the number of miles
(2 miles = .4+.4 = .4(2) =.8)
So for if the cost for Company A is "A"
Do the same thing for Company B but with the different numbers
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</span>
Find the number of miles in a day at which the rental costs for Company A and Company B are <span>the same</span>
"The same" here means equal so set the two equations equal to each other (that means the cost of Company A=the cost of Company B or A=B)
Now use algebra to solve for x
<span>
</span><span>
</span><span>
</span>
<span>
</span>
The answer is 500 miles.
</span>
So how you go about this problem is to first write an equation for how much each company will cost.
For Company A, it costs $120 plus some more.
The some more part can just be written as .4x where x is the number of miles
(2 miles = .4+.4 = .4(2) =.8)
So for if the cost for Company A is "A"
Do the same thing for Company B but with the different numbers
<span>
</span>
Find the number of miles in a day at which the rental costs for Company A and Company B are <span>the same</span>
"The same" here means equal so set the two equations equal to each other (that means the cost of Company A=the cost of Company B or A=B)
Now use algebra to solve for x
<span>
</span><span>
</span><span>
</span>
<span>
</span>
The answer is 500 miles.