Ask question

Ask question

All categories

pickupchik [31]

3 years ago

8

I’M MARKING BRAINLIEST!!!! I really need a good score pls help!

1 answer:

miv72 [106K]3 years ago

3 0

It’s just y=6 and x=-6

You might be interested in

A movie theater has a seating capacity of 333. The theater charges $5.00 for children, $7.00 for students,

pantera1 [17]

Answer:

182 children, 91 adults, 60 students

Step-by-step explanation:

The quantity of adults is x, then the quantity of children are 2x, the quantity of students is 333-x-2x=333-3x. The charge from all adults is 12x, students gave 7*(333-3x), children gave 5*2x=10x, the sum of all money is 2422

12x+ 7(333-3x)+10x=2422

12x+2331-21x+10x=2422

2331+x=2422

x=91- the amount of adults

1) 91*2=182- the amount of children

333-91-182= 60- the amount of students

6 0

3 years ago

The length of the race on sunday was 2 km. what is the length of 4 of those same races in meters?

muminat

1km=1000 meters so 2km=2000, and if you have 4 of the races you multiply 4 by 2000 which gives you 8000 meters
4*2000=8000

6 0

3 years ago

Read 2 more answers

Y=-5/3x + 28/3 in standard form

Temka [501]

3y + 5x - 28 = 0

anything please ask me

7 0

2 years ago

Read 2 more answers

Multiply k(5j+2) what is the answer to this please

AfilCa [17]

Use the distributive property to get 5kj+2k

8 0

2 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

3 years ago