Answer:
x² - 6x + 9
Step-by-step explanation:
(x - 3)² = x² - 6x + 9
Answer:
distance TS ≈ 19 m (nearest meter)
Step-by-step explanation:
The point T is on the horizontal ground and the angle of elevation of the top R of a tower is 63° and the height of the tower is 38 m high. The illustration forms a right angle triangle. The height RS of the tower is the opposite side of the triangle formed. The hypotenuse side of the triangle is the point from the ground T to the top of the tower R. The adjacent side of the triangle is the side TS.
using tangential ratio
tan 63° = opposite/adjacent
tan 63° = 38/adjacent
cross multiply
adjacent tan 63° = 38
divide both sides by tan 63°
adjacent side = 38/tan 63°
adjacent side = 38/1.96261050551
adjacent side = 19.3619670807
distance TS ≈ 19 m (nearest meter)
8x + 6 - 2x = 34x
Simplify 8x +6 - 2x to 6x + 6:
6x + 6 = 34x
Subtract 6x from both sides:
6 = 34x- 6x
Simplify 34x - 6x to 28x:
6 = 28x
Divide both sides by 28:
= x
Simplify
to
:
= x
Now switch sides and the answer is:
x =
:) <3
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
