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const2013 [10]
3 years ago
8

Conner has located a research source that is sponsored by a pharmaceutical company. Based on the sponsorship, Conner must be car

eful that the information is not
Computers and Technology
1 answer:
gogolik [260]3 years ago
6 0

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer is:

Conner has located a research source that is sponsored by a pharmaceutical company. Based on the sponsorship, Conner must be careful that the information is not <u>Biased.</u>

<u></u>

When you evaluate and use information from multiple sources, you need to evaluate the information that it must be error-free and not biased and it should be accurate information as you needed.

As in this example, Conner needs to research that the information should not be biased because the information or research source is sponsored by a pharmaceutical company and there is chances of biasedness. So, Conner must be careful that information is not biased.

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Write a program with total change amount as an integer input that outputs the change using the fewest coins, one coin type per l
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Answer:

#include<stdio.h>

#define DOLLAR 100

#define QUARTER 25

#define DIME 10

#define NICKEL 5

#define PENNY 1

void calculatedChange(int userAmount,int coinValues[])

{

if (userAmount >=100)

{

coinValues[0]=userAmount/DOLLAR;

userAmount=userAmount-(100*coinValues[0]);

}

if (userAmount >=25)

{

coinValues[1]=userAmount/QUARTER;

userAmount=userAmount-(25*coinValues[1] );  

}

if (userAmount >=10)

{

coinValues[2]=userAmount/DIME;

userAmount=userAmount-(10*coinValues[2]);

}

if (userAmount >=5)

{  

coinValues[3]=userAmount/NICKEL;

userAmount=userAmount-(5*coinValues[3]);

}

if (userAmount >=1)

{

coinValues[4]=userAmount/PENNY;

userAmount=userAmount-coinValues[4];

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}

int main() {

int amount;

printf("Enter the amount in cents :");

scanf("%d",&amount);

if(amount<1)

{

printf("No change..!");

}

else

{

int coinValues[5]={0,0,0,0,0};

calculatedChange(amount,coinValues);

if (coinValues[0]>0)

{

printf("%d Dollar",coinValues[0]);

if(coinValues[0]>1) printf("s");

}

if (coinValues[1]>0)

{

printf(" %d Quarter",coinValues[1]);

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if (coinValues[2]>0)

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printf(" %d Dime",coinValues[2]);

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printf(" %d Penn",coinValues[4]);

if(coinValues[4]>1) printf("ies");

else printf("y");

}

}

}

Explanation:

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