Answer:
Ven diagram is the answer.
Step-by-step explanation:
I don't think you were able to use a ven diagram from the start.
What we know is that a 6 foot tall tent casts a 15 foot shadow. Lets represent that given this way: 6 = 15
So, the unknown (y), or what we want to know, is how tall the cardboard box if it has a 6 foot long shadow (noticeably the same height as the tent):
y = 6
6 = 15
y = 6
(6 x 6) / 15 = y
36 / 15 = y
2.4 = y
The height of the cardboard box is 2.4 feet.
43.54 divided by 3.5= unit rate
12.44
The answer you are looking for is 1&1/3
F(a+h)=2(a+h)³=2(a³+3a²h+3h²a+h³)
the second choice is the correct answer.
