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katen-ka-za [31]
3 years ago
8

Help ASAP please ill give brainliest

Mathematics
1 answer:
Bad White [126]3 years ago
4 0
C
Hopes this helps!!!!!
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She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width 8.75 inches, length 8.75 i
jek_recluse [69]

Answer:

<h3><u>Part A</u></h3>

Dimensions of tank:

  • width = 8.75 in
  • length = 8.75 in
  • height = 23 in

⇒ Volume of each tank = width × length × height

                                       = 8.75 × 8.75 × 23

                                       = 1760.9375 in³

<h3><u>Part B</u></h3>

Given:

  • Hot coffee density = 5.8 oz/in³
  • Cold coffee density = 3.5 oz/in³

mass = density × volume

⇒ mass of hot coffee = 5.8 oz/in³ × 1760.9375 in³

                                     = 10213.44 oz (nearest hundredth)

⇒ mass of cold coffee = 3.5 oz/in³ × 1760.9375 in³

                                      = 6163.28 oz (nearest hundredth)

<h3><u>Part C</u></h3>

Convert the masses of the tanks from ounces to pounds

1 lb = 16 oz

⇒ mass of hot coffee tank = 10213.44 ÷ 16

                                            = 638.34 lb (nearest hundredth)

⇒ mass of cold coffee tank = 6163.28 ÷ 16

                                             = 385.21 lb (nearest hundredth)

If the table can hold a maximum of 800 lb:

hot coffee:  800 lb ÷ 638.34 lb = 1.25 (nearest hundredth)

cold coffee:  800 lb ÷ 385.21  lb = 2.08 (nearest hundredth)

Therefore, either:

  • 1 tank of hot coffee   <u>OR</u>
  • 2 tanks of cold coffee

can be placed on a table which can support a maximum weight of 800 lb

8 0
2 years ago
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