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2 years ago

Please helllppp . . . only give answer if you are 100% sure it's correct please!!

1 answer:

4 0

Condene the logarithms on the left side by applying the property, ln(a) - ln(b) = ln(a / b):

ln(x - 2) - ln(x - 3) = 1

→ ln((x - 2) / (x - 3)) = 1

Now take the exponential of both sides:

exp(ln((x - 2) / (x - 3))) = exp(1)

(x - 2) / (x - 3) = e

Solve for x :

x - 2 = e (x - 3)

x - 2 = e x - 3e

x - e x = 2 - 3e

(1 - e) x = 2 - 3e

x = (2 - 3e) / (1 - e) ≈ 3.582

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Find the area of the parallelogram

BartSMP [9]

6*14=84
the answer is 84cm²

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3 years ago

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What is 0.8% of 50? A. 0.04 B. 0.4 C. 4 D. 40

BaLLatris [955]

Answer:

It would be A!

Step-by-step explanation:

.08 times .50 would be 0.04. (It's a quick way to be able to solve problems similar to that! :)

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2 years ago

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Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

alina1380 [7]

Answer:

The answer is $x=a^{-1}cb^{-1}$ .

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element $g\in G$ there exist another element, denoted by $g^{-1}$ such that $gg^{-1}=e$ , where $e$ stands for the identity element of G.

So, given the equality $axb=c$ we make a left multiplication by $a^{-1}$ and we obtain:

$a^{-1}axb =a^{-1}c.$

But, $a^{-1}axb = exb = xb$ . Hence, $xb = a^{-1}c$ .

Now, in the equality $xb = a^{-1}c$ we make a right multiplication by $b^{-1}$ , and we obtain

$xbb^{-1} = a^{-1}cb^{-1}$ .

Recall that $bb^{-1}=e$ and $xe=x$ . Therefore,

$x=a^{-1}cb^{-1}$ .

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2 years ago

8. Evaluate 5y - 2x for x = 4 and y = 2.

kykrilka [37]

Answer:

Step-by-step explanation:

5y-2x

5(2)-2(4)

10-8=2

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2 years ago

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Evaluate the expression -7 1/4x + 3 5/8 for x= -4

Misha Larkins [42]

Answer:

32 5/8 (or 32 and 5/8)

Step-by-step explanation:

Okay, so this problem is asking for us to solve this problem with the substitution of a variable: x = -4. Before we fully solve this problem, we need to replace all of those x variables with -4 so that it is easier to solve.

-7 1/4(-4) + 3 5/8.

To make this problem even easier to solve, let's turn these mixed numbers into improper fractions. To do this, multiply the denominator by the whole number. Then add the numerator to this number. The new number that you just got is now your new numerator for this number.

-29/4(-4) + 3 5/8.

Repeat the last step to turn the other mixed number into an improper fraction.

-29/4(-4) + 29/8.

Now let's multiply that -4 by 29/4. Because a whole number technically has a denominator of 1, we can now set up the next part of our problem. (The symbol * means multiplication since we can't use x since it is already being used as a variable in this equation.)

(-29/4 * -4/1) + 29/8.

29 + 29/8.

Now to solve the rest of this problem, let's convert the whole number of 29 so that it has a denominator of 8. This is that these two numbers are addable.

29 x 8 = 232

1 x 8 = 8

Now these numbers are addable. So:

232/8 + 29/8 = 261/8 = 32 5/8.

I hope that this helps.

4 0

2 years ago