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Luden [163]
3 years ago
10

Please helllppp . . . only give answer if you are 100% sure it's correct please!!

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0

Condene the logarithms on the left side by applying the property, ln(<em>a</em>) - ln(<em>b</em>) = ln(<em>a</em> / <em>b</em>):

ln(<em>x</em> - 2) - ln(<em>x</em> - 3) = 1

→   ln((<em>x</em> - 2) / (<em>x</em> - 3)) = 1

Now take the exponential of both sides:

exp(ln((<em>x</em> - 2) / (<em>x</em> - 3))) = exp(1)

(<em>x</em> - 2) / (<em>x</em> - 3) = <em>e</em>

Solve for <em>x</em> :

<em>x</em> - 2 = <em>e</em> (<em>x</em> - 3)

<em>x</em> - 2 = <em>e x</em> - 3<em>e</em>

<em>x</em> - <em>e x</em> = 2 - 3<em>e</em>

(1 - <em>e</em>) <em>x</em> = 2 - 3<em>e</em>

<em>x</em> = (2 - 3<em>e</em>) / (1 - <em>e</em>) ≈ 3.582

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bazaltina [42]

The dP/dt of the adiabatic expansion is -42/11 kPa/min

<h3>How to calculate dP/dt in an adiabatic expansion?</h3>

An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression

Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min

PVᵇ = C

Taking logs of both sides gives:

ln P + b ln V = ln C

Taking partial derivatives gives:

\frac{1}{P}\frac{∂P}{∂t}  + \frac{b}{V}\frac{∂V}{∂t} = 0

Substitutituting the values b, P, V and dV/dt into the derivative above:

1/7 x dP/dt +  1.5/110 x 40 = 0

1/7 x dP/dt +  6/11 = 0

1/7 x dP/dt = - 6/11

dP/dt = - 6/11 x 7

dP/dt = -42/11 kPa/min

Therefore, the value of  dP/dt is -42/11 kPa/min

Learn more about adiabatic expansion on:

brainly.com/question/6966596

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4 0
1 year ago
What is 48, 100, 000, 000, 000 in scientific notation?<br><br> Can you please help me ASAP?
Afina-wow [57]

Answer:

4.81 x 10^13

Step-by-step explanation:

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3 0
3 years ago
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beks73 [17]
Y+5x=-3 step-by-step
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2 years ago
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Answer:

18. 46

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Step-by-step explanation:

absolute value means that the sign in front of the # doesn't matter, you just have to look at the positive value, for example:

absolute value of 46  =  46

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(imagine the sign in front of the # isn't there)

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3 years ago
Given that ∠A and ∠B are supplementary, Daisy conjectured that ∠A≅∠B . Which statement is a counterexample to Daisy's conjecture
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I believe the answer is C. 40 and 140.

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3 years ago
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