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pentagon [3]
2 years ago
10

Identify the domain and range of the relation. pls help

Mathematics
2 answers:
Pie2 years ago
8 0
Domain : 2,8,30,46
Range : -1,9,16
Alja [10]2 years ago
6 0
Domain – All of the values that go into a relation or a function are called the domain. Range – All of the entities (output) which emerge from a relation or a function are called the range. All input values that are used (independent values) forms the Domain set.
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Helen is preparing candy bags for the children at a party. she has 2 flavors of lollipops, 4 types of candy bars, and 6 flavors
yanalaym [24]
48 total combinations
multiply the 3 numbers together
7 0
4 years ago
At a baseball game henry bought 5 hot dogs and three bags of chips for $14.82. Scoot bought 7 hotdogs and 6 nags of chip for $22
laiz [17]

2.25

per hot dog

1.19

per bag o' chips

Explanation:

5x +3y = 14.82

7 x+6y = 22.89

− 10x−6y = −29.64

7 x+6y = 22.89

−3x  = −6.75

x=2.25

5⋅2.25+3y = 14.82

3y = 14.82  − 11.25

y = 3.57 /3  = 1.19

8 0
3 years ago
When x^3 + 2x^2 - 7x + a is divided by (x-2) the remainder is 4. Find the value of a. Please help
12345 [234]

Answer:

a = - 8

Step-by-step explanation:

A polynomial divided by factor (x - h) has a remainder given by f(h)

Here the divisor is (x - 2), thus f(2) gives the remainder, that is

2³ + 2(2)² - 7(2) + a = 4 ← 4 being the remainder

8 + 8 - 14 + a = 4, that is

12 + a = 4 ( subtract 12 from both sides )

a = - 8

5 0
3 years ago
_____ divided by 2/3=3/4<br>​
Lina20 [59]

Answer:

\frac{1}{2}

Step-by-step explanation:

Multiply the quotient \frac{3}{4} by the divisor \frac{2}{3} for the dividend, that is

\frac{3}{4} × \frac{2}{3}

Cancel the 3 on the numerator/ denominator

= \frac{1}{4} × \frac{2}{1} = \frac{2}{4} = \frac{1}{2}

4 0
3 years ago
If x&lt;5 and y&lt;6, then x+y__ 11<br> is it &lt;,&gt;,=?
Daniel [21]
To solve for this, let's try the highest number x and y can be.

X < 5, so it can be 4.
Y < 6, so it can be 5.

4 + 5 = 9.
9 < 11, so x + y < 11.

Your missing inequality symbol is:

<

I hope this helps!
7 0
4 years ago
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