No no no no no no no no no no no no
Answer:
0.1587
Step-by-step explanation:
Here, mean=μ=100 and standard deviation=σ=16.
We have to find P(average MDI scores of 64 children > 102)=P(xbar>102).
n=64
μxbar=μ=100
σxbar=σ/√n=16/√64=16/8=2
P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)
P(xbar>102)=P(z>1)
P(xbar>102)=P(0<z<∞)-P(0<z<1)
P(xbar>102)=0.5-0.3413
P(xbar>102)=0.1587
Thus, the probability that the average is greater than 102 is 15.87%
Answer:
Soh= sin= opp/hyp cah= cos=adj/hyp
toa= tan= opp/adj
Step-by-step explanation:
The 6 represents the thousands digit, and i think the 6 exactly 10 times the value is the 2 that is the tens place and 6 times 10 is 60.
