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2 years ago

6 snicker bars to 5 cookies.Write each ratio three differentways.a. Snickers to cookiesb. Cookies tosnickersc. Cookies to total

Mathematics

1 answer:

podryga [215]2 years ago

7 0

Answer:

a) Ratio of snickers to cookies = 6 : 5

b) Ratio of cookies to snickers = 5 : 6

c) Ratio of cookies to total = 5 : 11

Explanations:

Number of snicker bars = 6

Number of cookies = 5

Total = 6 + 5 = 11

a) Ratio of snickers to cookies = 6 : 5

b) Ratio of cookies to snickers = 5 : 6

c) Ratio of cookies to total = 5 : 11

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Solve by completing the square <br><br> 6x-x^2-7

Slav-nsk [51]

Answer:

6x-1/x^5

Step-by-step explanation:

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4 years ago

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F(x)=x 3−9xf, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 9, x What is the average rate of change of f over

mel-nik [20]

Answer:

$A(x) = 243$

Step-by-step explanation:

Given

$f(x) = x^3 - 9x$

$Interval: (12,6)$

Required

Determine the average rate of change

Average rate is calculated as thus;

$A(x) = \frac{f(b) - f(a)}{b - a}$

Calculating f(12)

$f(12) = 12^3 - 9 * 12$

$f(12) = 1728 - 108$

$f(12) = 1620$

Calculating f(6)

$f(6) = 6^3 - 9 * 6$

$f(6) = 216 - 54$

$f(6) = 162$

Substitute 12 for b and 6 for a in $A(x) = \frac{f(b) - f(a)}{b - a}$

$A(x) = \frac{f(12) - f(6)}{12 - 6}$

Substitute values for f(6) and f(12)

$A(x) = \frac{1620 - 162}{12 - 6}$

$A(x) = \frac{1458}{ 6}$

$A(x) = 243$

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3 years ago

Megan is making bracelets to sell to earn money for the local animal shelter it takes her 1/4 hour to pick out all the beads and

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She has 75mins to make braclets and it takes her 6mins to make one so 75 divided by 5 is your answer and if the answer is not a whole number round down

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3 years ago

What is 15/72 in simplest form

ss7ja [257]

15/72=5/24
Divide both by three.

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3 years ago

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Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

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3 years ago