We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
c.) 4 x (2)^x
Step-by-step explanation:
Answer:
In which x is the number of which we want to find the probability.
Step-by-step explanation:
For each traffic fatality, there are only two possible outcomes. EIther it involved an intoxicated or alcohol-impaired driver or nonoccupant, or it didn't. Traffic fatalities are independent of other traffic fatalities, which means that the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability is .40 that a traffic fatality involves an intoxication or alcohol-impaired driver or nonoccupant.
This means that
Eight traffic fatalities
This means that
Find the probability that the number which involve an intoxicated or alcohol-impaired driver or nonoccupant is
This is P(X = x), in which x is the number of which we want to find the probability. So
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