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Elan Coil [88]
2 years ago
14

0.98x0.23 what is 0.98 times 0.23?

Mathematics
1 answer:
fomenos2 years ago
3 0

Answer:

⠀⣴⠋⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡧⠀⠀⠀

⢸⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣾⣁⠀⠀⠀

⠈⠣⢴⡖⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢰⣤⣤⠶⣏⣠⡤⠀⣀⠀⣀⠀⠀⣠⡄⠀⠀⢀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠀⠉⠻⡦⠀

⠀⣰⡏⢀⡀⠀⢠⡄⠀⢀⡀⠀⠀⠀⠀⢸⠇⠀⠀⠉⠉⠛⠾⠿⡤⠟⠛⠛⠛⠳⠶⠺⣿⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠠⣤⠤⠴⠃⠀

⠀⢾⣤⣿⢀⡀⢸⡀⣠⣿⡇⠀⡀⠀⢠⡟⠀⠀⠀⠀⠀⠀⢞⣋⢉⡛⢦⡀⠀⠀⠀⠀⠙⠛⣯⠀⠀⠀⠀⠀⠀⠀⠀⠘⠻⣾⠁⠀⠀⠀

⠀⠀⠁⠉⡿⠀⠈⠉⣿⠘⠧⠼⠳⠶⠋⠀⠀⠀⠀⢀⣴⠟⠉⠁⠀⠁⠑⢷⡀⠀⠀⠀⠀⡰⠋⠀⠀⠀⠀⠀⣠⣤⢤⣄⠚⢻⠀⠀⠀⠀

⠀⠀⠀⠠⣇⣴⠄⠀⢻⠀⣀⠀⠀⠀⠀⠀⠀⠄⠠⡾⠃⠀⠀⠀⠀⠀⠀⠈⢷⠀⢢⡆⠀⠰⠶⡶⠀⠀⠀⣾⠋⠀⡀⢻⣧⠛⠛⣦⡀⠀

⠀⠀⠀⠀⠉⢿⣰⣇⢸⣇⡭⣑⡄⠀⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣀⣀⣀⡈⠀⠀⠁⠀⠀⠀⠙⣿⠁⢸⠇⠀⣼⣿⠀⢻⡂⠀⢸⡇⠀

⠀⠀⠀⠀⠀⠈⠁⠈⢹⠋⠀⠈⠻⡄⠰⠀⠀⠀⠀⠀⢠⡴⠒⠉⣉⣉⣉⣉⣹⣦⠀⠀⠀⠀⠀⠀⠈⠹⣸⠀⢠⣿⣿⡇⢸⡇⠀⠿⣄⠀

⠀⠀⠀⠀⠀⠀⠀⠀⢸⠀⠀⠀⠀⠀⠀⣀⠀⠀⠀⠀⢏⣡⠔⠋⠉⠉⠀⠀⠈⠁⠀⠀⠀⠀⠀⠀⠀⠀⠹⡆⢸⣿⣿⡇⣸⠇⠀⠀⢸⡇

⠀⠀⠀⠀⠀⠀⠀⠀⠈⠳⣶⠂⠉⣙⣻⣿⠀⠀⠀⠀⠘⠷⠶⠶⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠇⠀⠛⢹⡇⣿⠀⢠⣤⠞⠁

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠱⣤⡞⠁⠀⠹⣆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⠄⠀⠀⠀⠀⠀⢀⡤⠶⢮⣸⠏⠀⢀⡹⠂⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠻⣅⠀⠀⠀⢹⣆⠀⠀⢠⣤⡀⠀⠀⠈⠛⠿⠶⠶⠾⠛⠁⠀⠀⠀⣤⠀⠀⠸⣇⣀⣼⢡⣤⣤⠵⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠙⠷⣄⠀⠀⢿⡆⠀⢠⡿⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢹⡄⢸⡇⠀⠀⠈⣿⣶⣼⣿⣿⣄⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⢻⣆⠈⢷⠀⣾⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⡾⠁⣸⡿⠘⣷⣄⣿⣿⣿⣿⣿⣿⣧⣀⣠

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣽⡆⠈⠛⢁⣀⢀⣀⣀⣀⣀⣀⣤⣤⡴⠖⠛⠉⠀⣴⠟⠁⠀⣷⠙⠛⠿⢿⣿⡿⠿⠟⠋⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠻⣥⣿⣶⠛⠋⠉⠉⢉⣩⡭⠿⠟⠋⠁⠀⠀⠀⠀⠸⠀⠀⠀⠀⣘⣧⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⠏⠑⡶⠖⢻⠏⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⠈⢧⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣸⠇⠀⠈⢷⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⠙⡗⠒⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣴⠃⠀⠀⠀⢸⡇⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣸⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⡾⠏⠀⠀⠀⠀⢨⡇⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣠⠴⠞⠋⢹⡄⠀⠀⠀⢇⠀⠀⠀⠀⠀⠀⠀⠀⣀⣤⡴⠋⠀⠀⠀⠀⠀⠀⢸⠃⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⡤⠖⠋⠉⠀⠀⠀⠀⠀⠳⣄⠀⠀⢈⣁⣀⣤⡤⢴⣶⠿⠛⠋⠁⠀⠀⠀⠀⠀⠀⠀⢀⡏⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⣴⣾⣯⣥⣤⠤⢤⣤⣀⠀⠀⠀⠀⠀⠈⠉⠉⠉⠉⠀⠀⠀⠀⢿⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡾⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠙⠳⢤⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣼⣧⠀⠀⠀⠀⠀⠀⠀⠀⠀⣼⠃⠀⠀⠀⠀⠀⠀⠀⠀joe mama

Step-by-step explanation:

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Step-by-step explanation:

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If α, β are the zeroes of the polynomials f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) =
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f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

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