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Rainbow [258]
2 years ago
15

2^5*2^negative 3 simplify​

Mathematics
1 answer:
Citrus2011 [14]2 years ago
5 0

Answer:

4

Step-by-step explanation:

Simplify the following:

2^5/2^3

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to 2^5/2^3.

Combine powers. 2^5/2^3 = 2^(5 - 3):

2^(5 - 3)

Hint: | Subtract 3 from 5.

5 - 3 = 2:

2^2

Hint: | Evaluate 2^2.

2^2 = 4:

Answer: 4

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3 years ago
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The measure of an angle is three times the measure of its supplementary angle. What is the measure of each angle?
madreJ [45]

Answer:

45°

135°

Step-by-step explanation:

Let the measure of one angle be x

So, measure of its supplementary angle = 3x

\implies \: x  + 3x  = 180 \degree \\  \\  \implies \: 4x = 180 \degree  \\  \\\implies \: x = \frac{ 180 \degree}{4} \\  \\\implies \: x = 45 \degree \\  \\  \implies \: 3x  = 135 \degree

5 0
2 years ago
PLEASEEE HELP ME WHAT IS THE ANSWER!!
blagie [28]

Answer:

Number 3 is correct.

129.19m

Step-by-step explanation:

You might be wondering how did I got 32⁰, well, that's because they are alternate angles.

Now, we're trying to find the opposite side of the triangle.

Using the laws,

we got cos32⁰=x/243.8

243.8cos32⁰=x

129.19⁰

Mark me as Brian list?

3 0
2 years ago
Three lights all go on one changes every 5 sec one every 6 sec one every 8 sec when will they all go on together
inysia [295]
In order to calculate, you need to find their LCM
LCM of 5,6 and 8 is equal to 120

So, That time will be 120 sec = 2 min.
In short, Your Final Answer would be 2 min.

Hope this helps!
3 0
3 years ago
Help with five plz!!!!!
frutty [35]

Answer:

No there cannot be the same number of stickers on each page.

Step-by-step explanation:

If you want to find out how many stickers need to be in every page to be even you would add all the stickers up. 6+6+9+10+11= 42. Take the 42 and divide it by 5 to see how many stickers would go in each page. This will give you 8.4. However since this number is a decimal it can't be split evenly in whole stickers for each page. Meaning that it wouldn't be possible for each page to have a evenly distributed number of stickers per each page.

5 0
3 years ago
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