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Ira Lisetskai [31]
2 years ago
6

Could someone try to solve this for me?

Mathematics
1 answer:
Alik [6]2 years ago
8 0
276.46m² , hope I helped sorry I get it wrong
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A particle moves along the x-axis so that at any time t>0, its acceleration is given by a(t) = ln(3^t + 1). If the velocity o
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Step-by-step explanation:

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How do you find the area of a triangle?
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an air conditioning system can circulate 360, cubic feet of air per minute. how many cubic yards of air can it circulate per min
ahrayia [7]

Alright, lets get started.

3 feet = 1 yard

If we cube both sides of the equation, we will get the conversion into cubic yards

So,

3*3*3 cubic feet = 1 * 1*1 cubic yards

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13.33 cubic yards of air can it circulate per minute. : Answer

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3 0
3 years ago
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What is the equation of the quadratic graph with a focus of (-4,17/8) and a directrix of y=15/8
Temka [501]
So hmm notice the graph below

based on where the focus point is at, and the directrix, then, the parabola is opening upwards, meaning the squared variable is the "x"

\bf \begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}\\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}

now, keep in mind, the vertex is at coordinates h,k
the vertex itself is half-way between the focus and directrix
the directrix is at y=15/8 and the focus is at y=17/8
so, half-way will then be \bf \cfrac{17}{8}-\cfrac{15}{8}=\cfrac{2}{8}\iff \cfrac{1}{4}

well, so is 1/4 between the focus point and the directrix, half of that is 1/8
so, if you move from the focus point 1/8 down, you'll get the y-coordinate for the vertex, or 1/8 up from the directrix, since the vertex is equidistant to either

what's the "p" distance? well, we just found it, is just 1/8

so, the x-coordinate is obviously -4, get the y-coordinate by 17/8 - 1/8   or 15/8 + 1/8

and plug your values (x-h)² = 4p(y-k)   and then solve for "y", that's the equation of the quadratic

4 0
3 years ago
Find the distance between the points: (1,2) and (-3,0)
faltersainse [42]
You can create a right angled triangle.
Find the hypotenuse.
The third point of the triangle is (1,0)
using pythagoras, the value of a is 2, b is 3. 2^2 +3^2 = 13.
Therefore the distance between the two points is \sqrt{13}
7 0
3 years ago
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