Answer:
Step-by-step explanation:
Two train traveling in opposite direction
Distance apart the train is 120miles
Train A
Speed =30mph
Train B
90mph
What is common to the train is the same time, they will meet at the same time
Let assume they meet at distance x from from Washington
Then A has travelled x mile distance
Then, B has travelled 120-x mile distance
Time for train A to get to x,, = time for train B to get 120-x
Time=distance/speed
da/Sa=db/Sb
Let da be distance of train A
And db be distance of train B
Sa be speed of train A
Sb be speed of train B
Then,
da/Sa=db/Sb
x/30=120-x/90
Cross multiply
90x=3600-30x
90x+30x=3600
120x=3600
Then, x=3600/120
x=30miles
Then will meet at 30miles from Washington
Second part of the questions
Train B is faster than train A
Train B has already travelled 90miles while train B travels 30 miles
This shows that train A will not get to Baltimore before train B catch up
Then, let train A travel y distance
Then B will have to complete the 30 miles and then with another 30 miles that A has travel and then y
Total distance B travel will be
db=30+30+y
db=60+y
And da=y
Therefore,
da/Sa=db/Sb
y/30=60+y/60
Cross multiply
60y=1800+30y
60y-30y=1800
30y=1800
Then, y=1800/30
y=60miles
That means they will meet at 60miles from both Washington and Baltimore, or they are at mid points
