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Semenov [28]
2 years ago
10

Giren: Lines a and b Are perpendicular. Prove: <3 and <4 are complementary.

Mathematics
1 answer:
Nikolay [14]2 years ago
7 0
Since lines a and b are perpendicular, that means it is a right angles so angles a+b=90 so they are complementary
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AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC
sergejj [24]

Answer:

7x+5y-48=0

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A=(x_1,y_1) = (-3,-1)

Point B=(x_2,y_2) = (4,4)

Formula for slope 'm' when two points are given :

m=\frac{y_2-y_1}{x_2-x_1}

Substituting thew values

m=\frac{4-(-1)}{4-(-3)}

m=\frac{5}{7}

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

\Rightarrow m_1\times m_2 =-1

\Rightarrow \frac{5}{7}\times m_2 =-1

\Rightarrow m_2 = \frac{-7}{5}

So, Slope for line BC : m_2 = \frac{-7}{5}

Point B = (4,4)

Formula of equation of line : y-y_1=m(x-x_1)

y-4=\frac{-7}{5}(x-4)

5(y-4)=-7(x-4)

5y-20=-7x+28

7x+5y-20-28=0

7x+5y-48=0

Hence the equation of line BC : 7x+5y-48=0

5 0
3 years ago
Fun fact
pav-90 [236]

Answer: wow

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8 0
3 years ago
How do you say the number 4.293?<br> Also, write two other forms of this number.
Elodia [21]
Four point two-hundred ninety three
8 0
3 years ago
Read 2 more answers
BRAINLIEST can someone please help!!!!!
Zielflug [23.3K]

I don't know about the first one but for the second one:

{2}^{3x + 2}  -  {2}^{3x}  = 48 \\ \Leftrightarrow {2}^{3x}  {2}^{2}  -  {2}^{3x}  = 48 \\ \Leftrightarrow  {2}^{3x} ( 4  - 1) = 48 \\ \Leftrightarrow 3 \times  {2}^{3x}  = 48 \\ \Leftrightarrow  {2}^{3x}  = 16 \\ \Leftrightarrow  {2}^{3x}  =  {2}^{4}  \\ \Leftrightarrow 3x = 4\Leftrightarrow x =  \frac{4}{3}

4 0
3 years ago
√44 is between what 2 numbers?<br><br> A.4 and 5<br> B.5 and 6<br> C.6 and 7<br> D.7 and 8
Gemiola [76]
I believe the answer is C.

6 0
3 years ago
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