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KengaRu [80]
3 years ago
7

Which of the following functions represents exponential decay and has a y-intercept of 2?​

Mathematics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:A

Step-by-step explanation:

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It would be:  81*37.5 / 100 = 30.375
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If the sales tax rate in Tiffany's city is 7%, how much tax would she pay if a robot costs
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$23.646

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It would be an open circle with an arrow going to the right

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Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

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Solve the equation g^2-12g=-36​
Tresset [83]

\bold{Answer}

\boxed{\bold{G \ = \ 6}}

\bold{Explanation}

  • \bold{Solve: \ g^2-12g=-36}

\bold{---------------------}

  • \bold{Add \ 36 \ To \ Both \ Sides}

\bold{g^2-12g+36=-36+36}

  • \bold{Simplify}

\bold{g^2-12g+36=0}

  • \bold{Solve \ With \ Quadratic \ Formula}
  • \bold{a=1,\:b=-12,\:c=36:\quad g_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:36}}{2\cdot \:1}}

\bold{\left(-12\right)^2-4\cdot \:1\cdot \:36 \ = \ 0}

\bold{g_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{0}}{2\cdot \:1}}

\bold{g=\frac{-\left(-12\right)}{2\cdot \:1}}

  • \bold{Simplify \ \frac{-\left(-12\right)}{2\cdot \:1} \ = \ 6}

\bold{g=6}

\boxed{\bold{Eclipsed}}

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