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3 years ago

10

In a recent survey, 78% of students at Lincoln Middle School said they plan to attend a camp this summer. Write this percent as

a decimal

1 answer:

prohojiy [21]3 years ago

3 0

Answer:

<em>0.78</em>

Step-by-step explanation:

From the question, we are to represent 78% as a decimal

78% = 78/100

78/100 = 78 * 1/100

78/100 = 78 * 0.01

78/100 = 0.78

<em>hence the percent written as a decimal is 0.78</em>

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The height (in inches) of adult men in the United States is believed to be Normally distributed with mean μ . The average height

Jlenok [28]

Answer: a. 69.72 ± 1.37

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean height (in inches) of adult men in the United States.

Number of sample, n = 25

Mean, u = 69.72 inches

Standard deviation, s = 4.15

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z × standard deviation/√n

It becomes

69.72 ± 1.645 × 4.15/√25

= 69.72 ± 1.645 × 0.83

= 69.72 ± 1.37

The lower end of the confidence interval is 69.72 - 1.37 = 68.35

The upper end of the confidence interval is 69.72 + 1.37 = 71.09

5 0

3 years ago

If the annual interest rate is 2.8% then the weekly rate is

user100 [1]

Answer:

0.0538% (3 sf)

Step-by-step explanation:

annual = 1 yr = 12 months = 52 weeks

2.8% / 52 = 0.053846153

3 0

3 years ago

Let B be between a and C use the segment addition postulate to solve for W

fomenos

Answer:

Value of w = 6

Step-by-step explanation:

Given:

AB= 4w-4

BC = 2w-8

AC = 24

Find:

Value of w

Computation:

AB + BC = AC

4w - 4 + 2w - 8 = 24

6w - 12 = 24

6w = 24 + 12

6w = 36

w = 6

Value of w = 6

6 0

3 years ago

Austin has two Marvel posters he wants to hang on the wall in his bedroom. The wall is 16.5 feet wide and each poster is 5 3/4 f

vekshin1

The expression for the distance is w=5/3 ft

Step-by-step explanation:

The wall has a width of 16.5 feet

A single poster has a width of 5 3/4 ft which is equal to 23/4 ft or 5.75 ft

For the two posters, the width occupied is ; 23/4 * 2 = 23/2 = 11.5 ft

Remaining width that will be unoccupied by the posters will be 16.5-11.5=5

A sketch of the wall with the two posters such that the edge of the wall is the same as the distance between the posters will show three un-covered spaces, from edge of wall to the first poster, then between the two posters, and lastly from the second poster to the other edge of the wall.

The un-covered 3 portions have an equal width, lets assume that they have a width of w ft

This means 3w will represent the uncovered width which equals to the unoccupied space of 5 ft

Form equation for the uncovered width as;

3w=5ft

w=5/3 ft ---------the distance from the edge of each poster to the nearest edge of wall.

Learn More

Perimeter of a wall : brainly.com/question/12692838

Keyword :posters, wall, edge, distance

#LearnwithBrainly

6 0

3 years ago

Find the indefinite integral using the substitution x = 10 sin(θ). (Use C for the constant of integration.) 1 (100 − x2)3/2 dx

soldi70 [24.7K]

Answer:

The indefinite integral

= $\frac{1}{100}$ ˣ $\frac{x}{\sqrt{100-x^{2} } }$ ⁺ C

Step-by-step explanation:

x= 10sinθ

dx = 10cosθdθ

the step-to-step explanation is in the attachment

3 0

3 years ago