Find the nth term for the following sequences: Q2)3, 9, 15, 21
1 answer:
Answer:
= 6n - 3
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 9 - 3 = 15 - 9 = 21 - 15 = 6
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 3 and d = 6, then
= 3 + 6(n - 1) = 3 + 6n - 6 = 6n - 3
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To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A