Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
Answer:
45°
Step-by-step explanation:
A parallelogram is a polygon with 4 sides and 4 angles (that is a quadrilateral).
For a parallelogram ABCD, Opposite sides and opposite angles are equal (i.e. BC = AD and ∠A = ∠C).
Consecutive angles are supplementary that is ∠A + ∠B = 180°.
The diagonals of a parallelogram bisect each other also separating the parallelogram into two congruent triangles.
In parallelogram HIJK, ∠H and ∠J are opposite angles. hence:
∠H = ∠J (opposite angles of a parallelogram are equal)
∠J = 45°
5,280 feet per mile
10 miles
5,280x10= 52,800
Equivalent system, equivalent systema of equations
