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FinnZ [79.3K]
3 years ago
12

What division problem can be represented using the number line?

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0
A or b depending on wich way your moving
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the sum of two numbers is 54. if the greatest number is reduced by 20 and the lesser number tripled the difference of the two wo
elena-s [515]

Answer:

504

Step-by-step explanation:

4 0
3 years ago
Proving trapezoid theorems Geometry
Artist 52 [7]

Answer:

ΔABD ≅ ΔACD by SAS, therefore;

\overline {BD} \cong \overline {CA} by CPCTC

Step-by-step explanation:

The two column proof is presented as follows;

Statement {}                   Reason

ABCD is a trapezoid {}  Given

\overline {BA} \cong \overline {CD}  {}                   Given

\overline {BC} \parallel \overline {AD}   {}                   Definition of a trapezoid

ABCD is an isosceles trapezoid  {}    Left and right leg are equal

∠BAD ≅ ∠CDA  {}          Base angle of an isosceles trapezoid are congruent

\overline {AD} \cong \overline {AD}   {}                  Reflexive property

ΔABD ≅ ΔACD   {}         By SAS rule of congruency

\overline {BD} \cong \overline {CA}   {}                  CPCTC

CPCTC; Congruent Parts of Congruent Triangles are Congruent

SAS; Side Angle Side rule of congruency

8 0
3 years ago
Read 2 more answers
Find the product. 1.5m 6(-2m 2)4
sukhopar [10]
<span>1.5m^6 x (-2m^2)^4 = 1.5m^6 x (-2)^4 x (m^2)^4 = 1.5m^6 x 16 x m^8 = 24m^14 </span>
4 0
3 years ago
Read 2 more answers
In the figure, ∠4 is an exterior angle to ∠AUL.
marin [14]

a) Here, sum of two non-adjacent angles: 52 + 25 = 77

Now, ∠3 = 180 - 77   [ sum of all angles in a triangle is 180 ]

so, ∠3 = 103

Now, ∠3 + ∠4 = 180  [ Supplementary angles ]

So, ∠4 = 180 - ∠3

∠4 = 180 - 103 = 77

∠4 = 77 [ which is sum of two non-adjacent angles ]

....Hence proved.

b) m∠4 = 77 

[ Solved in previous section ]

Hope this helps!

3 0
3 years ago
Read 2 more answers
PLEASE REFER THE ATTACHMENT. THANK YOU ​
irina1246 [14]

The solution is given below:

<h3>What is price index?</h3>

An index number expressing the level of a group of commodity prices relative to the level of the prices of the same commodities during an arbitrarily chosen base period and used to indicate changes in the level of prices from one period to another.

Given:

Comm.         p0        q0       p1       q1       p0q0    p1q0       p1q1        p0q1

     A           25      750       30    960    18750      750       28800     24000

    B             30      450       25    550    13500     750       13750      16500

    C             5        250        6     360      1250     30        2160          1800

    D              6        90         7       210      540       42        1470           1260

    E               10        140       10     190     1400      100       1900          1900

     F                 4         48       5     65      192          240        365         260

Now,

\sump0q0 = 35632

\sump1q0 = 1912

\sump1q1 = 48445

\sump0q1= 45720

1) P01(L) = \sump1q0/\sump0q0 * 100

             = 5.36

2) P01(L) = \sump1q1/\sump0q1 * 100

            = 105.96

Dorbish- Bowley

= 5.36+ 105.96/2

=55.66

Marshall- Edgeworth

=  1912+  48445/35632 + 45720

= 50357/ 81352

= 0.619 *100= 61.9

Fisher's price index

=( 5.36 * 105.96 )^ 0.5

=23.831

Learn more about price index here:

brainly.com/question/14184515

#SPJ1

4 0
2 years ago
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