Answer:
0.2196
Step-by-step explanation:
Given that
Mean = 4.56 million visitors per day
Standard deviation = 820,000 visitors per day
According to the given situation the calculation of probability is shown below:-
Here we will find the value of P (3 ≤ X ≤ 4)



= 0.2483 - 0.0287
= 0.2196
Therefore the probability that the web site has between 3 million and 4 million visitors in a single day is 0.2196
Can you put spaces to make these easier to read? Plus, none of these have a horizontal asymphote of y = -3. At least if I’m understanding what you put correctly, A does have a vertical asymphote of x = -3 however.
Answer:
x = 8
Step-by-step explanation:
6x - 5 = 5x + 3
6x - 5x = 3 + 5 (combining like-terms)
x = 8
Hope this helps!
<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or
(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>
Answer:
363
Step-by-step explanation:
Formula for area of a circle
A = πr^2
Where r = radius
The circle has a given radius of 11
To find the area of the circle we simply substitute r in the formula with the value of the radius (11)
( Also note that the question says to use 3 for π )
A = πr^2
π = 3
r = 11
Substitute values in formula
A = (3)(11)^2
11^2 = 121
A = 121(3)
121(3) = 363
A = 363