6<span>√2 is already in it's simplest form as a radical.
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P is the point (2,k)
PA = PB
PA = √(49 + (2-k)²) and PB = √(1 + (6 - k)²)
√(49 + (2-k)²) = √(1 + (6 - k)²) => (49 + (2-k)² = (1 + (6 - k)²
=> 49 + 4 - 4k + k² = 1 + 36 - 12k + k² => 8k = 37 - 53 = -16 => k = -2
Answer:
y = -2x -3
Step-by-step explanation:
- the altitude trough F is a perpendicular line to the line DE
- find slope of line DE
D ( x2 = -5, y2 = -1); E (x1 = 3, y1 = 3)
slope m = (y2-y1) / (x2-x1) = (-1-3) / (-5-3) = -4/ -8 = 1/2
-find equation of the altitude trough F
lines that are perpendicular have the slope negative reciprocal (negative reciprocal of 1/2 is -2)
y= -2x +b , for point F(1, -5)
-5 = -2*1 +b, add 2 to both sides
-5 +2 = b, combine like terms
-3 =b
equation of the altitude trough F is y = -2x -3
Answer:
f
Step-by-step explanation:
