Find the perimeter of triangle ABC with vertices (2,4) (8,12) and (24,0)

1 answer:

3 0

Let
<span> A(2,4)
B(8,12)
C (24,0)

we know that
[perimeter of triangle]=AB+BC+AC

step 1
find the distance AB
d=</span>√[(12-4)²+(8-2)²]-----> dAB=√100------> dAB=10 units

step 2
find the distance BC
d=√[(0-12)²+(24-8)²]-----> dBC=√400------> dBC=20 units

step 3
find the distance AC
d=√[(0-4)²+(24-2)²]-----> dAC=√500------> dAC=22.36 units

[perimeter of triangle]=AB+BC+AC------> 10+20+22.36-----> 52.36 units

the answer is
the perimeter of triangle is 52.36 units

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