The translation of ABCD to A'B'C'D' is given by (×+[?].y-[ ]).

Mathematics

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

(x + 1 , y - 3)

Step-by-step explanation:

Compare x-coordinate of A(-6,1) and A'(-5,-2)

-6 + a = -5

a = -5 +6 = 1

x- coordinate of A' = x coordinate of A + 1

Compare y-coordinate of A(-6,1) and A'(-5,-2)

1 + a =-2

a = -2 - 1 = -3

y- coordinate of A' = y coordinate of A - 3

A(-6 , 1) = A'(-6+1 , 1-3) = A'(-5, -2)

D(( -1 , 1) = D'(-1+1, 1 - 3) = D'(0,-2)

C(-2,3) =C'(-2+1, 3-3) = C'(-1,0)

B(-4,3)= B'(-4+1 , 3-3) = B'(-3,0)

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