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3 years ago

7

The translation of ABCD to A'B'C'D' is given by (×+[?].y-[ ]).

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

(x + 1 , y - 3)

Step-by-step explanation:

Compare x-coordinate of A(-6,1) and A'(-5,-2)

-6 + a = -5

a = -5 +6 = 1

x- coordinate of A' = x coordinate of A + 1

Compare y-coordinate of A(-6,1) and A'(-5,-2)

1 + a =-2

a = -2 - 1 = -3

y- coordinate of A' = y coordinate of A - 3

A(-6 , 1) = A'(-6+1 , 1-3) = A'(-5, -2)

D(( -1 , 1) = D'(-1+1, 1 - 3) = D'(0,-2)

C(-2,3) =C'(-2+1, 3-3) = C'(-1,0)

B(-4,3)= B'(-4+1 , 3-3) = B'(-3,0)

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3 years ago

Please help me with this problem <br> Evaluate (-½·3)³

-Dominant- [34]

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Step-by-step explanation:

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2 years ago

Frank created a circle graph to show how he spent his time one day. He spent 8 hours at school, 8 hours sleeping, and the rest o

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3 years ago

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Step-by-step explanation:

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3 years ago

Factor completely: 2x4 − 32.

vazorg [7]

Answer:

Option b) is correct.

The completed factor of given expression is $2(x-2)(x+2)(x^2+4)$

Step-by-step explanation:

Given expression is $2x^4-32$

To find the completed factor for the given expression:

$2x^4-32$ :

Taking the common number "2" outside to the above expression we get

$2x^4-32=2(x^4-16)$

Now rewritting the above expression as below

$=2(x^4-2^4)$ (since 16 can be written as the number 2 to the power of 4)

$=2((x^2)^2-(2^2)^2)$

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Here $a=x^2$ and $b=2^2$

Therefore it becomes

$=2(x^2+2^2)(x^2-2^2)$

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The above expression is of the form $a^2-b^2=(a+b)(a-b)$

Here $a=x$ and $b=2$

Therefore it becomes

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Option b) is correct.

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